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mart [117]
4 years ago
11

16 plates in ? Stacks = 4 plates per stack

Mathematics
2 answers:
Ierofanga [76]4 years ago
3 0

Answer:

Step-by-step explanation:

that easy

Nastasia [14]4 years ago
3 0

Answer:

4

Step-by-step explanation:

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Find the value of x
AURORKA [14]
Hello Alondra,

To solve this problem, you have to write a proportion using the ratios formed by the similar triangles.

Or proportion can be:
x/(x+2) = 10/15

Cross multiply to solve it:
10x + 20 = 15x
20 = 5x
4 = x

The value of x is 4.

I hope this helps,
MrEQ
6 0
3 years ago
Does 4n = -20. = -24
Arada [10]
To solve 4n you need to divide both sides by 4
8 0
4 years ago
Rita earns $15 per hour. if she gets a 5% raise, what will her new hourly wage be
Agata [3.3K]

Answer:

$15.75

Step-by-step explanation:

five percent of 15 is 0.75. So you add that to 15 dollars and you get 15.75

5 0
4 years ago
Read 2 more answers
Simplify the ratio 24 / 36 . <br> 2 to 3 <br> 4 to 6 <br> 24 to 36<br> 3 to 8
AfilCa [17]
Both sides of the ratio can be divided by 12. 
24/12=2
36/12=3

So it would be a, 2 to 3.
7 0
4 years ago
Read 2 more answers
X -&gt; ∞ * (sqrt(x - a) - sqrt(bx))​
QveST [7]

Simplify the limand in the following way.

\displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \lim_{x\to\infty} \dfrac{\left(\sqrt{x-a}\right)^2 - \left(\sqrt{bx}\right)^2}{\sqrt{x-a} + \sqrt{bx}} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \lim_{x\to\infty} \frac{(x-a) - bx}{\sqrt x \left(\sqrt{1-\frac ax} + \sqrt b\right)} \\\\ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ = \lim_{x\to\infty} \frac{(1-b)\sqrt x - \frac a{\sqrt x}}{\sqrt{1 - \frac ax} + \sqrt b}

Now,

\displaystyle \lim_{x\to\infty} \frac a{\sqrt x} = 0

\displaystyle \lim_{x\to\infty} \sqrt{1-\frac ax} = \sqrt{1-\lim_{x\to\infty}\frac ax}} = \sqrt1 = 1

\implies \displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \frac{1-b}{\sqrt b} \lim_{x\to\infty} \sqrt x

and therefore

\displaystyle \lim_{x\to\infty} \left(\sqrt{x-a} - \sqrt{bx}\right) = \begin{cases} 0 & \text{if } b = 1 \\ -\infty & \text{if } b > 1\end{cases}

and does not exist otherwise.

7 0
2 years ago
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