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Katen [24]
2 years ago
10

PLEASE HELP

Mathematics
1 answer:
mr Goodwill [35]2 years ago
3 0

If 3 ft = 1yard

?        = 16 yards?

Thats \frac{16 yards * 3ft}{1yard}

The common values cancel each other out and you'll have 48 feet :)

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Andrew believes the honor roll students at his school have an unfair advantage in being assigned to the math class they request.
Artist 52 [7]
<span>                                                            Honor roll Not on honor roll Total
Received math class requested        315               64                   379
Did not get math class requested        41               80                   121
Total                                                        356             144                   500 

Honor roll: request granted: 315/356 = 0.88 x 100% = 88%
Not Honor roll request granted: 64/144 = 0.44 x 100% = 44%

Honor roll students were given preference in granting request than those not in the honor roll.</span>
5 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

3 0
3 years ago
Original price of a phone: $129.99<br> Tax: 2%
Solnce55 [7]

Answer:

$132.59 is the answer

3 0
2 years ago
Read 2 more answers
The ratio of women to men stationed at Ft. Bragg is 25 to 50. If there are 250 women at Ft. Bragg, how many people are there tot
WARRIOR [948]

Answer:

750 total people

Step-by-step explanation:

25 to 50 = 1/2

So: 250 x 2 = 500 men

500 + 250 = 750 total

7 0
3 years ago
Match the reasons with the statements in the proof.
natta225 [31]
<span>1. m∠6=m∠8, b||c
Given

2. m∠7=m∠8
</span><span>If lines ||, corresponding angles =.
</span><span>
3. m∠6=m∠7
</span>Substitution 
<span>
4. a||b </span>
If alternate interior angles equal, then lines ||. 
6 0
3 years ago
Read 2 more answers
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