X = 6y - 3
x + y = 53
6y - 3 + y = 53
7y - 3 = 53
7y = 53 + 3
7y = 56
y = 56/7
y = 8
x = 6y - 3
x = 6(8) - 3
x = 48 - 3
x = 45
ur numbers are : 8 and 45
The price of a staff ticket and the price of a student ticket is $8 and $14
Given:
Day 1:
Number of staff tickets sold = 3
Number of students tickets sold = 1
Total revenue day 1 = $38
Day 2:
<em>Number of staff tickets sold</em> = 3
<em>Number of students tickets sold</em> = 2
<em>Total revenue day</em> 2 = $52
let
<em>cost of staff tickets</em> = x
<em>cost of students tickets</em> = y
The equation:
<em>3x + y = 38 (1)</em>
<em>3x + y = 38 (1)3x + 2y = 52 (2)</em>
subtract (1) from (2)
2y - y = 52 - 38
y = 14
substitute y = 14 into (1)
3x + y = 38 (1)
3x + 14 = 38
3x = 38 - 14
3x = 24
x = 24/3
x = 8
Therefore,
cost of staff tickets = x
= $8
cost of students tickets = y
= $14
Read more:
brainly.com/question/22940808
It looks like there aren't many great matches for your search
Answer:
A
Step-by-step explanation:
Not 100% sure, been a while since i did this stuff but i think A is correct
