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In-s [12.5K]
3 years ago
10

Triangle has a base of 14 in. and a height of 6 in.

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0
(base x height)/2 good luck young one
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Please help with this maths question!??
tia_tia [17]

Answer:

2.44746×10⁶

Step-by-step explanation:

R=(3.8×10⁵)²/5.9×10⁴

=3.8²×10¹⁰/5.9×10⁴

=1.444×10¹¹/5.9×10⁴

=1.444×10⁷/5.9

=361×10⁷/1475

=2.44746×10⁶

4 0
3 years ago
A local school district requires all fourth graders to complete a 20-minute test containing 200 multiple-choice mathematics prob
Readme [11.4K]

The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

GIven,

A local school district requires all fourth graders to complete a 20-minute test containing 200 multiple-choice mathematics problems.

The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

The school district is assessing the rate because they are seeing how many questions students can answer in a given time frame.

Hence, The component of mathematics fluency is most likely the goal of this type of assessment is Rate.

Learn more about the Component of mathematics here brainly.com/question/24407396

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3 0
2 years ago
The points (4,8) and (6,g) fall on a line with a slope of –5. What is the value of g?
777dan777 [17]
<h3>Answer:  g = -2</h3>

======================================================

Explanation:

We will use the slope formula

m = (y2-y1)/(x2-x1)

Plugging in the given items leads to

-5 = (g-8)/(6-4)

Now solve for g

-5 = (g-8)/(6-4)

-5 = (g-8)/2

-5*2 = g-8

-10 = g-8

-10+8 = g

-2 = g

g = -2

We have (6,g) turn into (6,-2)

The two points (4,8) and (6,-2) are on a line of slope -5.

-------------------

As a way to check, we'll find the slope of the line through (4,8) and (6,-2)

m = (y2-y1)/(x2-x1)

m = (-2-8)/(6-4)

m = -10/2

m = -5

The answer is confirmed.

6 0
3 years ago
Which equation is represented by the graph below?
kirill115 [55]

Answer:

y = 2/3x + 6

Step-by-step explanation:

6 0
4 years ago
2) The foundations of any Euclidean geometry, at their most basic, exist on the principal concepts of which of
scZoUnD [109]
Answer is b- Theorems
3 0
3 years ago
Read 2 more answers
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