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In-s [12.5K]
3 years ago
10

Triangle has a base of 14 in. and a height of 6 in.

Mathematics
1 answer:
RoseWind [281]3 years ago
5 0
(base x height)/2 good luck young one
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the proper angle for a ladder is about 75 degrees. from the ground. suppose you have a 9 foot ladder. how far from the house sho
icang [17]

ANSWER:

2.33 foot

STEP-BY-STEP EXPLANATION:

We can calculate the distance from the staircase to the wall, by means of the trigonometric cosine ratio, which is the following:

\begin{gathered} \cos \theta=\frac{\text{ adjacent}}{\text{ hypotenuse}} \\ \theta=75\text{\degree} \\ \text{ hypotenuse = 9 foot} \\ \text{adjacent = x} \end{gathered}

Replacing and solving for x:

\begin{gathered} \cos 75=\frac{x}{9} \\ x=9\cdot\cos 75 \\ x=2.33 \end{gathered}

The distance would be 2.33 foot

3 0
11 months ago
Giuliana has 22 quarters and dollar coins worth a total of $10.75.Which equation can be used to find d, the number of dollar coi
Ganezh [65]
0.25(22 - d)+d=10.75
7 0
3 years ago
Read 2 more answers
The regular price for a sweater is $48. The store is having buy one get one 1/2 off sale. If you buy 2 sweaters for that price w
IRISSAK [1]
25%


If you are buying 2 shirts for the same price, you have to calculate the cost of the shirt at half price first (1 piece of the pie) and then add it the original price (2 equal pieces of the pie since you just divided that to the price of the second shirt). That would be considered 3 out of 4 pieces off the pie or 75%. Your savings would be 25%.
4 0
3 years ago
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Y+5=x+3 in standard form
podryga [215]

Answer: x-y=2

Step-by-step explanation:

y+5=x+3; move variable (x) to the left-hand side and change the sign.

y-x+5=3; move the constant to the right-hand side & change the sign

y+x=3-5; reorder the terms

-x+y=3-5; calculate

-x+y=-2; change the signs on both sides

x-y=2 is your answer! hope this helps!

7 0
2 years ago
After heating a fixed volume of gas at 50 psia from 300° R to 600°R, its pressure will be:
Vadim26 [7]

Answer:

100 psia

Step-by-step explanation:

Applying,

Pressure law,

P/T = P'/T'................. Equation 1

Where P = initial pressure, P' = Final pressure, T = initial temperature, P' = Final temperature.

make P' the subject of the equation

P' = PT'/T............ Equation 2

From the question,

Given: P = 50 psia, T = 300°R = (300×5/9)K = 166.66 K, T' = 600°R = (600×5/9)K = 333.33 K

Substitute these values into equation 2

P' = (50×333.33)/166.66

P' ≈ 100 psia

P ≈ 100 psia

4 0
2 years ago
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