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fomenos
3 years ago
5

Please help with this maths question!??

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

2.44746×10⁶

Step-by-step explanation:

R=(3.8×10⁵)²/5.9×10⁴

=3.8²×10¹⁰/5.9×10⁴

=1.444×10¹¹/5.9×10⁴

=1.444×10⁷/5.9

=361×10⁷/1475

=2.44746×10⁶

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castortr0y [4]
Is the 10 taking away 5 or was it meant to me 10.5 ?
6 0
3 years ago
Read 2 more answers
Can Someone please help me with this please please please
jasenka [17]

Answer:

About 5.5, but it is technically closer to 5.6 so I am not entirely sure

Step-by-step explanation:

Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:

\dfrac{x}{10}=\dfrac{10}{18} \\\\\\x=10\cdot \dfrac{10}{18}\approx 5.5

Hope this helps!

4 0
4 years ago
PLEASE HELP!!
baherus [9]

Answer:

How tall is he semicirlce?

Step-by-step explanation:

Then I can solve

4 0
3 years ago
An airplane descends 2.2 miles to an elevation of 8.55 miles. Find the elevation of the plane before its descent.
lutik1710 [3]

Answer:

10.75 miles was the elavation before it's decsecent.

Step-by-step explanation:

Hope this helps! :)

7 0
3 years ago
A marble is randomly selected from a bag. The probability of selecting a marble with dots on it is 0.2. The probability of selec
marin [14]

Answer:

0.5

Step-by-step explanation:

Let D be the event of selecting a marble with dots.

Let P be the event of selecting a purple marble.

The probability of selecting a marble with dots, P(D)=0.2

The probability of selecting a marble that is both purple and has dots, P(D \cap P)=0.1

We want to determine the probability of selecting a purple marble given that the marble has dots on it, P(P|D)

By the definition of conditional probability:

P(P|D)= \dfrac{P(P \cap D)}{P(D)} \\= \dfrac{0.1}{0.2}\\ =0.5

The probability of selecting a purple marble given that the marble has dots on it is 0.5.

4 0
3 years ago
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