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Zina [86]
3 years ago
13

Due in 10!!! Fill in the blanks…

Mathematics
1 answer:
Alenkinab [10]3 years ago
5 0

sorry this is late!!

#1 - A circular grid like this one can be helpful for performing dilations

#2 - To perform a dilation, we need a (In order to perform a dilation, students will need to know the center of dilation (which can be communicated using the coordinate grid), the coordinates of the polygon that they are dilating (also communicated using the coordinate grid), and the scale factor.)

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Stephanie surveyed the students in her class to find out their favorite color. her results are in the table. what percent of Ste
wariber [46]
Hi there!

To solve this problem, we need to find the amount of classmates out of the entire class who did not choose blue as their favorite color and then convert it into a percentage. 

First, let's find the fraction:

Since there are 25 total people in her class, since

6 + 9 + 10 = 25

25 is the denominator of the fraction;

Since there are 16 people who did not choose blue,

6 + 10 = 16

16 is the numerator of the fraction. 

So, our fraction is 16/25. 

Now, we need to convert it into a percentage. To do this, we need to make the denominator 100 by multiplying it by a certain number, and then multiplying the numerator by that same number so the fraction stays equal:

16/25 
= 16*4/25*4
= 64/100
= 64%

So, the answer is 64% of Stephanie's classmates.

Hope this helps!
3 0
3 years ago
Escribe el decimal que sea 1/10 de 3.0
Misha Larkins [42]
¡creo que la respuesta sería .3!
6 0
3 years ago
Which of the following properties can numbers have?
mr Goodwill [35]
They definitely can be positive they can be negative and they can have an absolute value but I would choose they both can be positive and negative
6 0
3 years ago
What are all the multiplication problems that make 2
makvit [3.9K]
If we're talking in whole numbers, the only multiplication of whole numbers that equals two is 
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6 0
3 years ago
Read 2 more answers
Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
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