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3 years ago

4x - 5y + 2xy = 0 Can Someone do this for me? I need help.

Mathematics

1 answer:

Nady [450]3 years ago

4 0

Answer: x = 5y/ 2y + 4

Step-by-step explanation: coz I juss know

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Jeremy raised $250 for charity last year. This year he raised 20% more than he raised last year. How much money did Jeremy raise

Lesechka [4]

You would find this by doing 250 times 20% which is .2 and you would get 50 so you would add 250 plus 50 and get 300.
The answer is $300

5 0

3 years ago

Read 2 more answers

Write an equation describing the relationship of the given variables. y varies inversely as the cube root of x and when x=125, y

notka56 [123]

Answer:

y = 40 / x^1/3

Step-by-step explanation:

Given that :

y α x^1/3

y = k * 1 / x^1/3

y = k / x^1/3

When x = 125 ; y = 8

8 = k / 125^1/3

Cube root of 125 = 5

8 = k / 5

8 * 5 = k ; k = 40

Hence, expression becomes :

y = 40 / x^1/3

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2 years ago

Identify the marked measurement

dem82 [27]

According to my examination I have confirmed that I do NOT repeat do NOT know this.

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3 years ago

The shelter has 90 dogs and 150 cats. of these animals 9 dogs and 27 cats receive medication. What percentage of animals receive

krek1111 [17]

3% because If you divide 27/9

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3 years ago

Susan threw a softball 42 years on her first try and 51 1/3 yard on her second try. How much farther did she throw the softball

Andru [333]

Answer:

28 feet farther than 1st ball.

Step-by-step explanation:

We have been given that Susan threw a softball 42 yards on her first try and $51\frac{1}{3}$ yard on her second try.

To find second ball is how much farther from the 1st ball, we will subtract 42 yards from $51\frac{1}{3}$ yards.

$\text{The second ball is farther from 1st ball}=51\frac{1}{3}\text{ yards}-42\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-42\text{ yards}$

Let us have a common denominator.

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{42*3}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154}{3}\text{ yards}-\frac{126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{154-126}{3}\text{ yards}$

$\text{The second ball is farther from 1st ball}=\frac{28}{3}\text{ yards}$

$\text{1 yard}=3\text{ feet}$

$\frac{28}{3}\text{ yards}=\frac{28}{3}\times 3\text{ feet}$

$\frac{28}{3}\text{ yards}=28\text{ feet}$

Therefore, Susan thrown the second ball 28 feet farther from the 1st ball.

7 0

3 years ago