Answer:
<h3>The picture in the attached figure.</h3><h3> </h3><h3>we know that </h3><h3> </h3><h3>Area of the triangle is equal to </h3><h3 /><h3> A= ( b×h ) /2</h3><h3> </h3><h3>in this problem </h3><h3> A=47 in²</h3><h3> </h3><h3> b=x</h3><h3> </h3><h3> h=x</h3>
<h3>so </h3><h3> 47 = X * X / 2</h3>
<h3> x² = 94 </h3><h3>
<h3> the answer is</h3>
Answer:
(0,0)
Step-by-step explanation:
We have,
U = { (x,y) : x,y belong to real numbers }
A = { (x,y) : (x,y) is a solution of y=x }
B = { (x,y) : (x,y) is a solution of y=2x }
We need to find the ordered pair (x,y) that belong to AB.
Let, (x,y) belong to AB
i.e. (x,y) belong to A and (x,y) belong to B
i.e. y = x and y = 2x
i.e. x = 2x
i.e. x = 0
Now, substitute x= 0 in any of the equation say y = x, we get y = 0.
Hence, the ordered pair satisfying AB is (0,0).
