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MA_775_DIABLO [31]
3 years ago
9

What would the answer be ? Thank You!!

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

2.33 = BC

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan B = AC / BC

tan 25 = AC / 5

Multiply each side by 5

5 tan 25 = BC

2.331538291 = BC

To the nearest hundredth

2.33 = BC

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2x-3y=3 5x+2y=17<br> how do i solve this?
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adding equation 1 and equation 2;
19x=57
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2x-3y=3
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if your cell phone bill was $67.82 and there's a 7.5% late fee how much will you pay for your phone bill
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$67.82 if you pay it on time.
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Is 6,000 g bigger than 6kg
Helen [10]

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<u>1 kilogram is 1,000 grams.</u>

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3 years ago
Show that 3 · 4^n + 51 is divisible by 3 and 9 for all positive integers n.​
Leni [432]

Answer:

To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;

3·4ⁿ is divisible by 3 and 51 is divisible by 3

Where we have;

S_{(n)} =  3·4ⁿ + 51

S_{(n+1)} = 3·4ⁿ⁺¹ + 51

S_{(n+1)} - S_{(n)} = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ

S_{(n+1)} - S_{(n)} = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ

∴ S_{(n+1)} - S_{(n)} is divisible by 9

Given that we have for S₀ =  3×4⁰ + 51 = 63 = 9×7

∴ S₀ is divisible by 9

Since  S_{(n+1)} - S_{(n)} is divisible by 9, we have;

S_{(0+1)} - S_{(0)} =  S_{(1)} - S_{(0)} is divisible by 9

Therefore S_{(1)} is divisible by 9 and S_{(n)}  is divisible by 9 for all positive integers n

Step-by-step explanation:

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