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Paraphin [41]
3 years ago
11

As part of proof find the midpoint of PQ

Mathematics
1 answer:
Zanzabum3 years ago
6 0

P(0,0) and Q(2a , 0)

Midpoint PQ

x = (x1 + x2)/2 and y = (y1 = y2)/2

Midpoint:

x = (2a +0)/2

= 2a / 2

= a

y = (0+ 0)/2

= 0/ 2

= 0

So midpoint PQ (a , 0)

Answer is the 1st option

(a, 0)

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Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 45 of the number of part 1 que
vesna_86 [32]

Given :

Stephanie took a science exam that had two parts. Part 1: She got 16 questions correct, which was 4/5 of the number of part 1 questions. Part 2: She got 16 questions correct, which was 2/3 of the number of part 2 questions.

To Find :

The total number of questions on Stephanie's exam.

Solution :

Let, number of questions in Part 1 is x :

16=\dfrac{4}{5}x\\\\x=20

Let, number of questions in Part 2 is y :

16=\dfrac{2}{3}y\\\\y=24

Therefore, total number of questions on Stephanie's exam are 20 + 40 = 60.

Hence, this is the required solution.

5 0
3 years ago
I can’t figure out the surface area. Someone please help !! :)
Ilia_Sergeevich [38]
<h3> Answer:</h3><h2>surface area is 227•1</h2><h2>volume is 321•7</h2>

Step-by-step explanation:

diameter is 8•5

radius is d/2

8•5/2

=4•25

surface area = 4πr^2

4×22/7×4•25×4•25

=1589•5/7

=227•1

Volume= 4/3πr^3

4/3×22/7×4•25×4•25×4•25

4/3×22/7×76•76

=321•7

Hope it helps

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5 0
2 years ago
The LB Company has long manufactured a light bulb with an average life of 5400 hours. Company researchers have recently develope
elena55 [62]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the average life of light bulbs.

As per given , we have

Null hypothesis : H_0 : \mu =5400

Alternative hypothesis : H_a : \mu >5400

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Formula for Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=95,\ \overline{x}=5483\ \&\ \sigma=500, we have

z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180

Using z-value table , Critical one-tailed test value for 0.06 significance level :

z_{0.06}=1.5548

 Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .

[We reject the null hypothesis when critical value is less than the test statistic value .]

Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life

8 0
3 years ago
2. What is the slope of the line that passes through the points M(-5,0) and N (6,8)?
Oxana [17]

Answer:

Hi how are you doing today Jasmine

6 0
3 years ago
What is the constant of proportionality in this relationship ???? Help fast !!!
photoshop1234 [79]

Answer:

3.28

Step-by-step

(3,18.85)

(2,12.57)

18.85-12.57/3-2=3.28

3 0
3 years ago
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