Given:
Mean, μ = 196
Std. dev., σ = 22
A sample size of 50 (> 30) is large enough to provide meaningful data.
The random variable is x = 200.
The z-score is
z = (x - μ)/σ = (200 - 196)/22 = 0.1818
From normal distribution tables, obtain
Prob(X < 200) = 0.572 = 57.2%
Answer: 57.2%
Answer:
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Step-by-step explanation:
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Answer:
1:9
Step-by-step explanation:
6×60=360min
40:360
1:9
Answer:
I think there is a mistake somwhere . Please can someone else try it out
