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kondor19780726 [428]
3 years ago
14

A company uses a computer program to create coupon codes for customers to use on its website. The codes are made up from the sym

bols !, #, &, *, as well as any letter from the alphabet.
The company uses the program to make a code, one character at a time.

What is the probability the first character is a symbol?

Please answer as a decimal rounded to the nearest hundredth.
Mathematics
2 answers:
Alja [10]3 years ago
6 0
0.15 is the answer. Hope this helps!
AnnyKZ [126]3 years ago
6 0
Total number of possible outcomes= 4 symbols + 26 letters =30 outcomes

Event is getting a symbole.

P(symbole) = 4/30 =0.13
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~**Will mark brainliest **~<br> For the correct answers to all three questions
aleksandr82 [10.1K]

a)

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b)

\dfrac{21}{32}\cdot\dfrac{39}{120}\cdot\dfrac{40}{65}=\dfrac{21}{32}\cdot\dfrac{3\cdot13}{2\cdot2\cdot2\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot2\cdot5}{5\cdot13}=\\\\\\=\dfrac{3\cdot7}{32}\cdot\dfrac{13}{2\cdot2\cdot2\cdot5}\cdot\dfrac{2\cdot2\cdot2}{13}=\dfrac{21}{32}\cdot\dfrac{1}{5}\cdot\dfrac{1}{1}=\dfrac{21}{160}

c)

\dfrac{15}{90}\cdot\dfrac{36}{75}\cdot\dfrac{27}{42}=\dfrac{3\cdot5}{2\cdot3\cdot3\cdot5}\cdot\dfrac{2\cdot2\cdot3\cdot3}{3\cdot5\cdot5}\cdot\dfrac{3\cdot3\cdot3}{2\cdot3\cdot7}=\\\\\\=\dfrac{1}{2\cdot3}\cdot\dfrac{2\cdot2\cdot3}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{1}\cdot\dfrac{2}{5\cdot5}\cdot\dfrac{3\cdot3}{2\cdot7}=\dfrac{1}{25}\cdot\dfrac{9}{7}=\dfrac{9}{175}

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KengaRu [80]

Answer:

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Step-by-step explanation:

8 0
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SOVA2 [1]

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Step-by-step explanation:

(2x^3+11x^2+5)-(x^3-2x^2+2)

Clearing brackets

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3 years ago
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Answer:

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-4m + 8m = -16
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