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kondor19780726 [428]
3 years ago
14

A company uses a computer program to create coupon codes for customers to use on its website. The codes are made up from the sym

bols !, #, &, *, as well as any letter from the alphabet.
The company uses the program to make a code, one character at a time.

What is the probability the first character is a symbol?

Please answer as a decimal rounded to the nearest hundredth.
Mathematics
2 answers:
Alja [10]3 years ago
6 0
0.15 is the answer. Hope this helps!
AnnyKZ [126]3 years ago
6 0
Total number of possible outcomes= 4 symbols + 26 letters =30 outcomes

Event is getting a symbole.

P(symbole) = 4/30 =0.13
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Decrease £120 by 45%
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120 * 45  % =  120 *0,45  =  54 £

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3 years ago
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Jack is trying to make extra money on his summer vacation from school. He works two different jobs, earning $9 per hour washing
Sveta_85 [38]

Answer:

$57

9w+6d

Step-by-step explanation:

Given that:

Earnings per hour for washing cars = $9

Earnings per hour for walking dogs = $6

Number of hours for which car washing is done = w

Number of hours taken for walking dogs = d

Earnings for w hours for washing cars = Per hour earnings multiplied by number of hours = $9w

Earnings for d hours for walking dogs = Per hour earnings multiplied by number of hours = $6d

Total earnings by both = $(9w+6d)

Now, given that

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Number of hours spent walking dogs = 2 hours

Therefore, total earnings by both = 9 \times 5 + 6 \times 2 = <em>$57</em>

5 0
3 years ago
Solve mathematics question, please:) Unanswered re-asked question.
Fiesta28 [93]
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and when multiply by negative, flip sign

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3 0
3 years ago
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A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func
djyliett [7]

Answer:

y=120 * 1.1^x --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

x \to months

y \to mice

So, we have:

(x_1,y_1) = (0,120) --- Monday

(x_2,y_2) = (1,132) --- One month later

Required

The function

The function is represented as:

y=ab^x

In (x_1,y_1) = (0,120), we have:

120 = a * b^0

120 = a * 1

120 = a

a=120

In (x_2,y_2) = (1,132), we have:

132 = a * b^1

132 = a * b

Substitute: a=120

132 = 120 * b

Solve for b

b = \frac{132}{120}

b = 1.1

So, the function is:

y=ab^x

y=120 * 1.1^x

To calculate the monthly rate (r), we have:

y =a(1 + r)^x

Compare to: y =ab^x

1 + r = b

Make r the subject

r = b-1

Substitute b = 1.1

r = 1.1-1

r = 0.1

Express as percentage

r = 0.1*100\%

r = 10\%

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3 years ago
(6c^2-c+1)-(-4c+2c^2+8c)
Natalka [10]
6c^2 - c + 1 + 4c - 2c^2 - 8c
= 4c^2 - 5c + 1
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3 years ago
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