Question

PLEASE HELP!!!!! !!!!!!!!!!!!

Answer 1

Answer:

31.9secs

6,183.3m

Step-by-step explanation:

Given the equation that models the height expressed as;

h(t ) = -4.9t²+313t+269

At the the max g=height, the velocity is zero

dh/dt = 0

dh/dt = -9,8t+313

0 = -9.8t + 313

9.8t = 313

t = 313/9.8

t = 31.94secs

Hence it takes the rocket 31.9secs to reach the max height

Get the max height

Recall that h(t ) = -4.9t²+313t+269

h(31.9) = -4.9(31.9)²+313(31.9)+269

h(31.9) = -4,070.44+9,984.7+269

h(31.9) = 6,183.3m

Hence the maximum height reached is 6,183.3m