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Bess [88]
3 years ago
11

PLEASE HELP!!!!! !!!!!!!!!!!!

Mathematics
1 answer:
valina [46]3 years ago
3 0

Answer:

31.9secs

6,183.3m

Step-by-step explanation:

Given the equation that models the height expressed as;

h(t ) = -4.9t²+313t+269

At the the max g=height, the velocity is zero

dh/dt = 0

dh/dt = -9,8t+313

0 = -9.8t + 313

9.8t = 313

t = 313/9.8

t = 31.94secs

Hence it takes the rocket 31.9secs to reach the max height

Get the max height

Recall that h(t ) = -4.9t²+313t+269

h(31.9) = -4.9(31.9)²+313(31.9)+269

h(31.9) = -4,070.44+9,984.7+269

h(31.9) = 6,183.3m

Hence the maximum height reached is 6,183.3m

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Solve the system of equations by multiplying and adding. Enter the solution as an ordered pair.
GREYUIT [131]

Answer:

(x, y) = (- 3, 4)

Step-by-step explanation:

Given the 2 equations

5x + 2y = - 7 → (1)

4x - y = - 16 → (2)

multiply all terms in (2) by 2

8x - 2y = - 32 → (3)

Add (1) and (3) term by term

(5x + 8x) + (2y - 2y) = (- 7 - 32)

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substituting in (1) gives

(5 × - 3) + 2y = - 7

- 15 + 2y = - 7 ( add 15 to both sides )

2y = 8 ( divide both sides by 2 )

y = 4

solution is (- 3, 4 )


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