Answer:
Refer to the explanation.
Step-by-step explanation:
Let's take each one at a time.
1.
To solve for the complement, we simply subtract our markup rate by 100%.
100% - 30% = 70%
Now to solve for the selling price, we use the formula


Selling Price = $123.91
2.
We do the same process with the first number.
100% - 40% = 60%


SellingPrice = $366.67
3.
The same as the first two.
100% - 20% = 80%


SellingPrice = $111.88
4.
Now to solve for the markup rate, we use the formula:

In this case we first need to find the markup. The markup is the difference between the selling price and the cost.
Selling Price = $235.28
Cost = $199.99
Markup = $235.28 - $199.99
Markup = $35.29
Now the we know our markup, we can then solve for the markup rate using the formula.


MarkupRate = 0.1499 x 100 = 14.99% or 15%
5.
Now for the last one, we need to find for the cost. Let's use the selling price formula to find for the cost.

Selling Price = $30.77
Complement = 65% or 0.65
This will then give us.

We multiple both sides of the equation by 0.65 to leave our cost alone.
30.77 x 0.65 = Cost
Cost = $20
Subtract 2m from both sides : 4m + 3 = -2
Subtract 3 from both sides : 4m = -1
Divide by 4 on both sides : m = -1/4
Answer:
Domain: All real numbers Range: (-∞, -31/8]
Step-by-step explanation:
Since the parent function for this equasion is y=x^2, you know that the graph wil be parabolic in shape. All parabolic functions have a domain of all real numbers. Now when you rewrite the graph in vertex form, you will see that the top vertex is at y=-31/8, this is going to restrict the range to be (-∞, -31/8]. I have provided a graph using the app PhotoMath.
Answer:
H0: μ ≥ 16
H1: < 16
−2.748749;
0.011275;
Reject the Null
Step-by-step explanation:
Given the data:
15.87, 16.02, 15.78, 15.83, 15.69, 15.81, 16.04, 15.81, 15.92, 16.10
Null hypothesis ; H0: μ ≥ 16
Alternative hypothesis ; H1: < 16
Sample size, n = 10
From the data:
Using calculator,
Sample mean, m = 15.887
Standard deviation, s = 0.13
The test statistic, T
(m - μ) / s/sqrt(n)
(15.887 - 16) / (0.13/sqrt(10))
= −2.748749
Using the p value from test statistic calculator :
Degree of freedom (df) = 10 - 1 = 9 at 0.05 significance level is 0.011275
Since the p value is < 0.05
0.011 < 0.05
We reject the Null and conclude that the mean fill weight is less than 16 oz