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Scorpion4ik [409]
3 years ago
11

The net of square pyramid is shown below. What is the surface area of the pyramid?

Mathematics
2 answers:
stich3 [128]3 years ago
6 0
To find surface area, you must find the normal area of every side of a shape and add it together.

<u>Square
</u>
<u /><u />A=l*w
A=8*8
A=64

<u>Triangles
</u>
<u /><u />A=1/2 b*h
A=1/2 8*8
A=32

<u>Combined Area
</u>
<u /><u />32*4= 128

128+64=192

The surface area of this figure is D. 192cm.

miv72 [106K]3 years ago
4 0
The surface area of that pyramid is 192 cm^2
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Answer:

1) (x + 3)(3x + 2)

2) x= +/-root6 - 1 by 5

Step-by-step explanation:

3x^2 + 11x + 6 = 0 (mid-term break)

using mid-term break

3x^2 + 9x + 2x + 6 = 0

factor out 3x from first pair and +2 from the second pair

3x(x + 3) + 2(x + 3)

factor out x+3

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rearrange the equation

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divide both sides by 5 to cancel out the 5 of first term

5x^2/5 + 2x/5 - 1/5 = 0/5

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rearranging the equation to gain a+b=c form

x^2 + 2x/5 = 1/5

adding (1/5)^2 on both sides

x^2 + 2x/5 + (1/5)^2 = 1/5 + (1/5)^2

(x + 1/5)^2 = 1/5 + 1/25

(x + 1/5)^2 = 5 + 1 by 25

(x + 1/5)^2 = 6/25

taking square root on both sides

root(x + 1/5)^2 = +/- root(6/25)

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shifting 1/5 on the other side

x = +/- root6 /5 - 1/5

x = +/- root6 - 1 by 5

x = + root6 - 1 by 5 or x= - root6 - 1 by 5

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