To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.
H'(t) = -32t + 64
Now find the critical numbers:
-32t + 64 = 0
-32t = -64
t = 2 seconds
Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):
H'(1) = 32
H'(3) = -32
As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.
To find the height, plug t=2 into H(t):
H(2) = -16(2)^2 +64(2) + 30 = 94
The answer is 94 ft at 2 sec.
Answer:
d
Step-by-step explanation:
inverse property of addition is going back to zero with the equation so adding 2 to negative 2 will go back to zero
Answer:
(1, 3)
Step-by-step explanation:
Given the expression
x+y = 4 ... 1
y = 2x+1 ....2
Substitute equation 2 into 1
x + (2x+1) = 4
3x + 1 = 4
3x = 4-1
x = 3/3
x = 1
Since y = 2x + 1
y = 2(1) + 1
y = 3
Hence the solution to the equation is (1,3). This means that the coordinate point on the graph where both lines intersect will be at (1, 3)
Answer:
To find a, b, and c, rewrite in the standard form ax2+bx+c=0ax2+bx+c=0.
a=1, b=3, c=0
