8.544 is the sqare root with a remainder
Answer:
the answer is a
Step-by-step explanation:
It’s A because 2+3=5 and 5x7=35
Step-by-step explanation:
(-x)-12=16
-x=28
x=28
plss mark brainliestttt
Step-by-step explanation:
Hey there!
Given sequences are; 2 , 13 , 24 , 35 , _ , _ .
Now,
Common difference (d) = 2nd term - 1st term. = 13-2 = 11
When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.
Now, let's find the nrh term of the sequence.
nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)
nth = 2+ (n-1) 11
= 2 + 11n - 11
= 11n - 9
Let's check if we have got nth term correct.
a1= 1*11 - 9 = 2
a2 = 2*11-9 = 13
a3 = 3*11 - 9 = 24
a4 = 4*11-9 = 35
So, we got our nth term.
Let's find remaining sequence.
a5= 5*11 - 9 = 46.
a6= 6*11 - 9 = 57.
Therefore, the remaining terms are : 46 and 57.
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
