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2 years ago

Please help me Look at the image

Mathematics

1 answer:

Leto [7]2 years ago

3 0

Answer:

74 degrees

Step-by-step explanation:

As sum of interior and exterior at a vertex add to 180, subtract 106 from 180 to get 74 degrees

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What is the area of a sector with a central angle of 2pi/9 radians and a diameter of 20.6mm? Use 3.14 for Ali and round your ans

LuckyWell [14K]

- The area of the circle is:

A=πr²

A is the area of the circle.
π=3.14
r is the radius of the circle.

- To calculate the area of <span> the sector indicated in the problem, you must apply the following formula:

As=(</span>θ/2π)πr²

As is the area of the sector.
θ is the central angle (θ=2π/9)
π=3.14
r is the radius.

- First, you must find the radius:

r=Diameter/2
r=20.6 mm/2
r=10.3 mm

- Now, you can substitute the values into the formula As=(θ/2π)πr². Then, you have:

As=(θ/2π)πr²
As=(2π/9/2π)(π)(10.3)²
As=(π/9π)(π)(10.3)²
As=(3.14/9x3.14)(3.14)(10.3)²

- Finally, the area of the sector is:

As= 37.01 mm²

6 0

3 years ago

Read 2 more answers

Janie is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?

UkoKoshka [18]

Answer:

Option (D) is correct.

No, They will not intersect.

Step-by-step explanation:

Given Points for g(x), (1,2) , (2,4) and (3,6)

Since g is a linear function then it must be in form of g(x) = mx +c where, c is constant and m is slope.

We first calculate the slope using,

$m=\frac{y_2-y_1}{x_2-x_1}$

Here, consider $x_1=1 , x_2=2 , y_1=2, y_2=4$

Substitute above, we get slope as,

$m=\frac{4-2}{2-1}=2$

Thus, equation becomes g(x) = 2x + c ...(1)

For c plug the values in (1),

(1,2) ⇒ 2= 2 + c ⇒ c = 0

Thus, Equation of G(x) is 2x.

When we plot it it do not intersect f(x).

Thus, Option (D) is correct.

No, They will not intersect.

3 0

3 years ago

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A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o

vivado [14]

Since $\rho=\dfrac mV$ (density = mass/volume), we can get the mass/weight of the liquid by integrating the density $\rho(x,y,z)$ over the interior of the tank. This is done with the integral

$\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx$

which is more readily computed in cylindrical coordinates as

$\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}$

7 0

3 years ago

Please help!!!! With this problem

aleksley [76]

I can't see the page it is glitches out try reopening it

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2 years ago

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ElenaW [278]

If you follow is rule : P(x,y)>180° rotation>P'(-x,-y). the negative signs doesn't mean to make it negative but to change it to the opposite sign. If it's positive it goes to negative. And if it's negative is goes to positive. The rotated image would have the points: (1,2) (4,4) (3,7)

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3 years ago

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