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3 years ago

11

Hallie is helping put away dishes in the school cafeteria . She is stacking bowls to put into the cupboard. If she has 62 bowls

and can put a maximum of 4 bowls in each stack , what is the minimum number of stacks hallie will have ?

2 answers:

poizon [28]3 years ago

7 0

15 and a half stack but I would round to 16

aliina [53]3 years ago

3 0

The minimum number of Halle will have 15 stacks.

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Determine if the table is proportional or nonproportional

Step2247 [10]

The answer is nonproportional.

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3 years ago

Read 2 more answers

PLEASE I NEED HELP URGENTLLY, AND PLEASE SHOW WORK

kvasek [131]

Answer:

Ok, so I say that the answer is 100

5 0

3 years ago

What is the simplified form of the following expression?

USPshnik [31]

Option C:

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

Solution:

Given expression is

$$\sqrt[3]{\frac{4 x}{5}}$

Note: $\sqrt[3]{125}=\sqrt[3]{{5^3}} = 5$

To find the correct expression for the above simplified expression.

Option A: $\frac{\sqrt[3]{4 x}}{5}$

5 can be written as $\sqrt[3]{125}$ .

$$\frac{\sqrt[3]{4 x}}{5}=\frac{\sqrt[3]{4 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{4x}{125} }$

It is not the given simplified expression.

Option B: $\frac{\sqrt[3]{20 x}}{5}$

$$\frac{\sqrt[3]{20 x}}{5}=\frac{\sqrt[3]{20 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{20x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4x}{25} }$

It is not the given simplified expression.

Option C: $\frac{\sqrt[3]{100 x}}{5}$

$$\frac{\sqrt[3]{100 x}}{5}=\frac{\sqrt[3]{100 x}}{\sqrt[3]{125} }$

$$=\sqrt[3]{\frac{100x}{125} }$

Cancel the common factor in both numerator and denominator.

$$=\sqrt[3]{\frac{4 x}{5}}$

It is the given simplified expression.

Option D: $\frac{\sqrt[3]{100 x}}{125}$

$$\frac{\sqrt[3]{100 x}}{125}=\frac{\sqrt[3]{100 x}}{5^3}$

It is not the given simplified expression.

Hence Option C is the correct answer.

$$\frac{\sqrt[3]{100 x}}{5}=\sqrt[3]{\frac{4 x}{5}}$

3 0

3 years ago

16. An employee has to pay 15.5% in taxes. If

lilavasa [31]

Answer:

379.75

Step-by-step explanation:

15.5 x 2450

100

= 379.75

7 0

3 years ago

a company owns two dealerships, both of which sell cars and trucks. the first dealership sells a total of 164 cars and trucks. t

OLEGan [10]

Answer:

294 cars.

Step-by-step explanation:

Let x be the number of cars and y be the number of trucks.

We have been given that the first dealership sells a total of 164 cars and trucks. We can represent this information as:

$x+y=164...(1)$

The second dealership sells twice as many cars and half as many trucks as the first dealership. So the number of cars sold by 2nd dealership will be 2x and number of trucks sold by 2nd dealership will be y/2.

Further, the 2nd dealership sold a total of 229 cars and trucks. We can represent this information as:

$2x+\frac{y}{2}=229...(2)$

We can see that total number of cars sold on two dealerships will be $x+2x=3x$ .

We will use substitution method to solve for x. From equation (1) we will get,

$y=164-x$

Substituting this value in equation (2) we will get,

$2x+\frac{164-x}{2}=229$

Now let us have a common denominator.

$\frac{4x}{2}+\frac{164-x}{2}=229$

$\frac{4x+164-x}{2}=229$

Upon multiplying both sides of our equation by 2 we will get,

$2\times \frac{4x+164-x}{2}=2\times 229$

$4x+164-x=458$

$4x+164-164-x=458-164$

$4x-x=458-164$

$3x=294$

Therefore, the total number of cars sold by two dealerships is 294.

7 0

4 years ago