Answer:
(y^2)/4 square meters
Step-by-step explanation:
For a perimeter length of x, the side of a square will be x/4 and its area will be (x/4)^2.
If one side of the square is shortened by y/2 and the adjacent side is lengthened by y/2, then the difference in side lengths will be y. The area of the resulting rectangle will be ...
(x/4 -y/2)(x/4 +y/2) = (x/4)^2 -(y/2)^2
That is, the difference in area between the square and the rectangle is ...
(x/4)^2 - ((x/4)^2 -(y/2)^2) = (y/2)^2 = y^2/4
The positive difference between the area of the square region and the area of the rectangular region is y^2/4 square meters.
(-3,-6) this is the answer you can also double check by plugging it into a calculator
The answer is: [B]: " 9 * 10⁻³ " .
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y-intercept -3
slope 1/2
is sufficient info with which to write an equation for a straight line:
y = mx + b becomes y = (1/2)x - 3.
You should check this by determining whether or not (2,-1) satisfies this equation.
