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4 years ago

Does anybody know how to write 45/70 in simplest form????

Mathematics

2 answers:

sasho [114]4 years ago

6 0

Divide both numbers by five.
You should get 9/14

EleoNora [17]4 years ago

4 0

First you have to divide, so the answer is 9/14. Hope this helps! :)

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What number would you add to both sides of x2 + 7x = 4 to complete the square?

Nata [24]

Answer:

12.5

Step-by-step explanation:

(7/2) = 3.5

(3.5)^2 = 12.5

8 0

4 years ago

Shalnov [3]

Answer:

x = 54

y = 47.5

Step-by-step explanation:

If two lines p and q are parallel and line r is a transversal intersecting these lines at two different points,

(x + 56)° = (2x + 2)° [corresponding angles]

2x - x = 56 - 2

x = 54

Similarly, lines r and s are parallel lines and q is a transversal line intersecting these lines,

(y + 7)° + (3y - 17)°= 180° [Consecutive exterior angles]

4y - 10 = 180

4y = 190

y = 47.5

3 0

3 years ago

Each of

vova2212 [387]

The median is 12.

The arithmetic mean is 12.7

The geometric mean is 11.3

4 0

3 years ago

Simplify 1/3(9a+b)-1/2(4a+2b)

d1i1m1o1n [39]

1/3 x 9a then 1/3 x n plus -1/2 x 4a the -1/2 x 2b the add the two b's together then add the two a'S together the write _a + _b

6 0

4 years ago

Read 2 more answers

Suppose a random sample of 200 Americans is asked to disclose whether they can order a meal in a foreign language. Describe the

taurus [48]

Answer:

The distribution of sample proportion Americans who can order a meal in a foreign language is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, <em>n</em> = 200.

The sample selected is quite large.

The Central limit theorem can be applied to approximate the distribution of sample proportion.

The distribution of sample proportion is,

$\hat p\sim N(p,\ \sqrt{\frac{p(1-p)}{n}})$

3 0

3 years ago