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Naily [24]
2 years ago
11

A basket contains the following pieces of fruit: 3 apples, 4 oranges, 4 bananas, 2 pears, and 3 peaches. Jonas picks a fruit at

random and does not replace it. Then Beth picks a fruit at random. What is the probability that Jonas gets an orange and Beth gets a peach?
Mathematics
1 answer:
yuradex [85]2 years ago
8 0

Answer:

Probability that Jonas gets an orange is 1/4 and Beth gets a peach is 3/16.

Step-by-step explanation:

Here,

The total number of fruits n(S) = 3 + 4 + 4 + 2 + 3

= 16

The total number of oranges n(O) = 4

The total number of peas n(P) = 3

Now,

P(O) = n(O)/n(S)

= 4/16

= 1/4

Again,

P(P)= n(P)/n(S)

= 3/16

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The ratio of Wei Ling's age to Wei Xuan's age 5 years ago was 2: 5. In 9 years
Archy [21]

Answer:

15 years old

Step-by-step explanation:

Start by defining the variables that we are going to use throughout our working:

Let the current age of Wei Ling and Wei Xuan be L and X years old respectively.

Next, form equations using the given information.

<u>5 years </u><u>ago</u>

Wei Ling: (L -5) years old

Wei Xuan: (X -5) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan's is 2: 5,

\frac{ L - 5}{X - 5}  =  \frac{2}{5}

Cross multiply:

2(X -5)= 5(L -5)

Expand:

2X -10= 5L -25

2X= 5L -25 +10

2X= 5L -15 -----(1)

<u>9 years time</u>

Wei Ling: (L +9) years old

Wei Xuan: (X +9) years old

Given that the ratio of Wei Ling's age to that of Wei Xuan is 3: 4,

\frac{L + 9}{X + 9}  =  \frac{3}{4}

Cross multiply:

3(X +9)= 4(L +9)

Expand:

3X +27= 4L +36

3X= 4L +36 -27

3X= 4L +9 -----(2)

Let's solve using the elimination method.

(1) ×3:

6X= 15L -45 -----(3)

(2) ×2:

6X= 8L +18 -----(4)

(3) -(4):

6X -6X= 15L -45 -(8L +18)

0= 15L -45 -8L -18

0= 7L -63

7L= 63

L= 63 ÷7

L= 9

Substitute L= 9 into (1):

2X= 5(9) -15

2X= 45 -15

2X= 30

X= 30 ÷2

X= 15

Thus, Wei Xuan is 15 years old now.

6 0
2 years ago
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