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timurjin [86]
3 years ago
12

Which inequality statement describes the two numbers on a number line? "6 and a number 10 units to the left of 6" A) 10 > 6 B

) 10 < 6 C) −4 > 6 D) −4 < 6
Mathematics
1 answer:
almond37 [142]3 years ago
4 0

Option D

- 4 < 6   inequality statement describes the two numbers on a number line

<u>Solution:</u>

Given, statement is "6 and a number 10 units to the left of 6"  

We have to find which inequality statement describes the two numbers on a number line?

Now, we know that, as we move towards left on the number line, the value goes decreasing by 1 for every one unit.

So, a number 10 units to the left of 6 will be 6 – 10 = - 4  

So, the two numbers are 6, -4 and we know that, - 4 < 6

Hence, option D is correct.

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Solve for the value of r. (8r+6)° (9r-7)​
lukranit [14]

Answer:

r = 13

Step-by-step explanation:

these angles are vertical and are congruent

8r + 6 = 9r - 7

6 = r - 7

13 = r

8 0
2 years ago
Find an equation of the line that passes through the point (4, 3) and is perpendicular to the line 2x + 9y − 6 = 0.
vesna_86 [32]
Perpendicular has the reciprocal slope and u have to put the point given into point slope.

y-3=9/2(x-4)

(The slope of the original equation was -2/9)
3 0
3 years ago
Which is bigger, 7/8" or 9/16"?
Iteru [2.4K]
7/8 and 9/16

7*2/8*2 = 14/16

14/16 and 9/16

Now since we have a common denominator, we can compare the numerators.

14/16 is greater, so 7/8 is greater than 9/16

Answer: 7/8 is bigger
5 0
3 years ago
Read 2 more answers
Point G is (-8,6) Point J is a reflection of point G and is reflected across the x axis what are the coordinates of point J?
kakasveta [241]

Answer:

(-8, -6)

Step-by-step explanation:

Given the Point G is (-8,6) if Point J is a reflection of point G and is reflected across the x axis, to get the coordinate of point J, we will negate the y coordinate while retaining the x coordinate value

J = (-8, -(6))

J = (-8, -6)

Hence the required coordinate of J is (-8, -6)

7 0
2 years ago
If NTM is congruent to OUM, SP is congruent to SQ, S is the center of the circle, and OM = 18, find NT. Round the answer to the
Aleks [24]
OM=18, so OQ=QM=18/2=9.
 Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
4 0
3 years ago
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