Answer:
a(c-b) = d
Use the distributive property, which states: x(y-z) = xy - xz
a(c-b) = ac - ab
ac - ab = d
Add ab on both sides
ac = d + ab
Divide both sides by a to isolate c
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Answer:
it could be 1/1 or 2/2 or 3/3 or 4/4 or 5/5 or 6/6 it is the same thing just put the number like how i did depending on the question
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
:)
Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
Answer:
2/3
Step-by-step explanation: