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fomenos
4 years ago
10

How to solve inequaities?

Mathematics
1 answer:
Elza [17]4 years ago
3 0

-3(-8+5m) > 5(6-3m)\qquad|\text{use distributive property}\\\\(-3)(-8)+(-3)(5m) > (5)(6)+(5)(-3m)\\\\24-15m > 30-15m\qquad|\text{add 15m to both sides}\\\\24 > 30\qquad FALSE\\\\\text{Therefore your answer:}\ \boxed{NO\ SOLUTION}\to m\in\O

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Which expression is equivalent to 8√6<br>a √14<br>b √48<br>c √96<br>d √384
Anestetic [448]

Answer:

Option d. is the correct choice.

Step-by-step explanation:

8 can be written as √8 x √8 = √64

So, given expression will become:

= √64 x √6

= √384

Best Regards!

7 0
3 years ago
Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value. Find that value and explain how you know.
Naya [18.7K]

Answer:

x=-1 is a maximum vaue.

Step-by-step explanation:

To find the minimum and maximum values of the function f(x), we're going to derivate it:

f(x) = –5x^2 – 10x + 6 ⇒ f'(x) = -10x - 10

The points where f'(x) is zero, could be a maximum or a minimum. Then:

f'(x) = -10x - 10 = 0 ⇒ x=-1

Now, to know if x=-1 is a maximum or a minimum, we need to evaluate the original function for x when it tends to -1 from the right and from the left.

Therefore:

For x=-2:

f(x) = 6 (Positive)

For x=0:

f(x) = 6 (Positive)

For x=-1

f(x) = 11 (Positive)

Given that at x=-1, f(x) = 11, and then it goes down to 6 when x=0, we can say that it's a maximum.

4 0
4 years ago
Read 2 more answers
A projectile is launched from ground level at an angle of 13.0 ° above the horizontal. It returns to ground level. To what value
Elden [556K]

Answer:

The launch angle should be adjusted to 30.63°

Step-by-step explanation:

The range of a projectile which is the horizontal distance covered by the projectile can be expressed as;

R =(v^2 sin2θ)/g

Where

R = range

v = initial speed

θ = launch angle

g = acceleration due to gravity

For the case above. When the projectile is launched at angle 13° above the horizontal.

θ1 = 13

R1 = (v^2 sin2θ1)/g

R1 = (v^2 sin26°)/g ....1

For the range to double

R2 = (v^2 sin2θ)/g .....2

R2 = 2R1

Substituting R2 and R1

(v^2 sin2θ)/g = 2 × (v^2 sin26°)/g

Divide both sides by v^2/g

sin2θ = 2sin26

2θ = sininverse(2sin26)

θ = sininverse(2sin26)/2

θ = 30.63°

3 0
3 years ago
14 + 72 x 1/10 + 4 x 1/1000 =
Naily [24]

Answer:

21.204

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The table shows the color preferences of 50 shoppers at the mall. What is the probability that one shopper, selected random from
Sladkaya [172]
20/50=2/5=0.4=40%
2/5 or 0.40 or 40%
They're all equal.
Hope this helps :)
5 0
4 years ago
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