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Anestetic [448]

3 years ago

8

A person earns $187.42 before deductions for 3 days work . What is the rate of per hour assuming 8 hours of work per day ?

1 answer:

klemol [59]3 years ago

6 0

They earn $7.81 an hour

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(6 x 9 = f) f x 16 = b <br><br> what dose b equal

Tcecarenko [31]

Step-by-step explanation:

f=6×9

aubstituting f=6×9

6×9×16=b

864=b

4 0

2 years ago

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Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Solve using a proportion.

Advocard [28]

Answer:

t = 24 yards

Step-by-step explanation:

Since the trapezoids are similar then the ratios of corresponding sides are equal, that is

$\frac{t}{c}$ = $\frac{u}{d}$

Substitute in given values

$\frac{t}{0.4}$ = $\frac{15}{0.25}$ ( cross- multiply )

0.25t = 6 ( divide both sides by 0.25 )

t = 24

5 0

2 years ago

Multiply (x-4)(x^2-5x-6) ...?

frez [133]

See attached photo for answer.

6 0

3 years ago

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At one baseball stadium, there are 4 kinds of seats .what fraction of the total seats are premium

bija089 [108]

Assuming that each kind of seat is unnique and different from each other
( assume 4 kinds, premium, gold, silver, bronze, or premium, not premium, not premium, not premium)

so fraciton is parts out of whole so

1 out of 4 toal parts is 1/4

7 0

3 years ago