Wake up to reality! Nothing ever goes as planned in this world. The longer you live, the more you realize that in this reality only pain, suffering and futility exist.- Madara Uchiha
Answer:
The adult and the child ticket are both 8 dollars
Step-by-step explanation:
x =adult ticket price
y = child ticket price
I will assume you forget to put that they sold 2 child tickets on the second day
7x+5y=96 and 3x+2y= 40
I will use elimination. Multiply the first equation by 2 and the second equation by -5 to eliminate y
2(7x+5y)=96*2
14x + 10y = 192
The second equation
-5(3x+2y)= 40*-5
-15x -10y = -200
Add the equations together
14x + 10y = 192
-15x -10y = -200
------------------------
-x = -8
Multiply by -1
x = 8
Now we need to find y
3x+2y= 40
3(8) +2y = 40
24+2y = 40
Subtract 24 from each side
24-24 +2y = 40-24
2y = 16
Divide by 2
2y/2 =16/2
y =8
The adult and the child ticket are both 8 dollars
I think its sides ae congruent and sides are congruent
Answer:
deez
Step-by-step explanation:
beacuse deez is the problem solver to everthing duh
If \dfrac{x-1}{3}=k 3 x−1 =kstart fraction, x, minus, 1, divided by, 3, end fraction, equals, k and k=3k=3k, equals, 3, what i
earnstyle [38]
For this case we have the following expression:
(x-1) / (3) = k
Substituting the value of k = 3 we have:
(x-1) / (3) = 3
From here, we must clear the value of x.
We have then:
x-1 = 3 * 3
x-1 = 9
x = 9 + 1
x = 10
Answer:
The value of x is given by:
x = 10
