Question

Factor p^2−6−q·(p^2−6)^2

Answer 1

Answer:

(p^2−6) (1-q(p^2-6))

Step-by-step explanation:

p^2−6−q·(p^2−6)^2

Put parentheses around the P^2-6 at the beginning of the expression

(p^2-6) -q (p^2−6)^2

Factor out (p^2−6)

(p^2−6) (1-q(p^2-6))

Answer 2

Assignment: $\bold{Factor \ Equation: \ p^2-6-q\left(p^2-6\right)^2}$

<><><><><><><>

Answer: $\boxed{\bold{\left(p^2-6\right)\left(-p^2q+6q+1\right)}}$

<><><><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><><><>

[ Step One ] Factor Out Common Term $\bold{\left(p^2-6\right)}$

$\bold{\left(p^2-6\right)\left(-q\left(p^2-6\right)+1\right)}$

[ Step Two ] Expand $\bold{-q\left(p^2-6\right)+1}$

$\bold{-p^2q+6q+1}$

[ Step Three ] Rewrite Equation

$\bold{\left(p^2-6\right)\left(-p^2q+6q+1\right)}$

<><><><><><><>

$\bold{\rightarrow Mordancy \leftarrow}$