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3 years ago

How to solve (4x 3 + 7y 3z 4) 2

1 answer:

8 0

My work:

Simplifying (4x3 + 7y3z4)(4x3 + 7y3z4) = 0 Multiply (4x3 + 7y3z4) * (4x3 + 7y3z4) (4x3 * (4x3 + 7y3z4) + 7y3z4 * (4x3 + 7y3z4)) = 0 ((4x3 * 4x3 + 7y3z4 * 4x3) + 7y3z4 * (4x3 + 7y3z4)) = 0 Reorder the terms: ((28x3y3z4 + 16x6) + 7y3z4 * (4x3 + 7y3z4)) = 0 ((28x3y3z4 + 16x6) + 7y3z4 * (4x3 + 7y3z4)) = 0 (28x3y3z4 + 16x6 + (4x3 * 7y3z4 + 7y3z4 * 7y3z4)) = 0 (28x3y3z4 + 16x6 + (28x3y3z4 + 49y6z8)) = 0 Reorder the terms: (28x3y3z4 + 28x3y3z4 + 16x6 + 49y6z8) = 0 Combine like terms: 28x3y3z4 + 28x3y3z4 = 56x3y3z4 (56x3y3z4 + 16x6 + 49y6z8) = 0 Solving 56x3y3z4 + 16x6 + 49y6z8 = 0 Solving for variable 'x'. Factor a trinomial. (4x3 + 7y3z4)(4x3 + 7y3z4) = 0 Subproblem 1Set the factor '(4x3 + 7y3z4)' equal to zero and attempt to solve: Simplifying 4x3 + 7y3z4 = 0 Solving 4x3 + 7y3z4 = 0 Move all terms containing x to the left, all other terms to the right. Add '-7y3z4' to each side of the equation. 4x3 + 7y3z4 + -7y3z4 = 0 + -7y3z4 Combine like terms: 7y3z4 + -7y3z4 = 0 4x3 + 0 = 0 + -7y3z4 4x3 = 0 + -7y3z4 Remove the zero: 4x3 = -7y3z4 Divide each side by '4'. x3 = -1.75y3z4 Simplifying x3 = -1.75y3z4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. Subproblem 2Set the factor '(4x3 + 7y3z4)' equal to zero and attempt to solve: Simplifying 4x3 + 7y3z4 = 0 Solving 4x3 + 7y3z4 = 0 Move all terms containing x to the left, all other terms to the right. Add '-7y3z4' to each side of the equation. 4x3 + 7y3z4 + -7y3z4 = 0 + -7y3z4 Combine like terms: 7y3z4 + -7y3z4 = 0 4x3 + 0 = 0 + -7y3z4 4x3 = 0 + -7y3z4 Remove the zero: 4x3 = -7y3z4 Divide each side by '4'. x3 = -1.75y3z4 Simplifying x3 = -1.75y3z4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined. The solution to this equation could not be determined.
Hope that this help you! =)

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A Gardner wants to add 39 pounds of nutrient a and 16 pounds of nutrient b to her garden. Each bag of brand x provides 3 pounds

ehidna [41]

Answer:

5 bags of brand x and 6 bags of brand y.

Step-by-step explanation:

Nutrient requirement for the garden:

39 pounds of nutrient a and

16 pounds of nutrient b

Component of each bag of brand x:

3 pounds of nutrient a and 2 pounds of nutrient b

Therefore, 5 bags of brand x will contain 15 pounds of nutrient a and 10 pounds of nutrient b

Component of each bag of brand y:

4 pounds of nutrient a and 1 pound of nutrient b

Therefore, 6 bags of brand y will contain 24 pounds of nutrient a and 6 pounds of nutrient b

Altogether, she should buy 5 bags of brand x and 6 bags of brand y to meet the nutrient requirement of the garden

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3 years ago

The formula for the volume sphere is V=4/3pie r^3 what is the formula solved for r?

oksian1 [2.3K]

Answer:

$r = \sqrt[3]{\frac{3V}{4 \pi}}$

Step-by-step explanation:

From the formula of volume of a sphere we have to isolate "r" on one side of the equation i.e. we have to make "r" the subject of the equation.

$V=\frac{4}{3} \pi r^{3}\\\\ \text{Multiplying both sides by 3/4 we get}\\\\\frac{3V}{4} = \pi r^{3}\\\\ \text{Dividing both sides by } \pi \\\\ \frac{3V}{4 \pi} = r^{3}\\\\\text{Takeing cube root of both sides}\\\\\sqrt[3]{\frac{3V}{4 \pi}} = r$

Therefore:

$r = \sqrt[3]{\frac{3V}{4 \pi}}$

3 0

3 years ago

Read 2 more answers

Please give me correct answer and fast answer it if know answer only

Stolb23 [73]

Answer:

Approximatley 5.8 units.

Step-by-step explanation:

We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

$\frac{\sin(A)}{a}=\frac{\sin(B)}{b} =\frac{\sin(C)}{c}$

Replacing them with the respective variables, we have:

$\frac{\sin(S)}{s} =\frac{\sin(T)}{t} =\frac{\sin(R)}{r}$

Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for t. Ignore the third term:

$\frac{\sin(20)}{s}=\frac{\\sin(17)}{5}$

Solve for s, the unknown side. Cross multiply:

$\frac{\sin(20)}{s}=\frac{\sin(17)}{5}\\5\sin(20)=s\sin(17)\\s=\frac{5\sin(20)}{\sin(17)} \\s\approx5.8491\approx5.8$

6 0

3 years ago

Read 2 more answers

Distance between (-7,-6) and (-2,-16)

Archy [21]

Exact form:

2 $\sqrt\ 13$

Decimal form:

7.21110255 or 7.21

5 0

2 years ago

Read 2 more answers

I need the answers for these pls help

DanielleElmas [232]

Answer:

A. m arc QRS = 100°

B. m arc QRT = 255°

C. m arc UTS = 180°

D. m arc UTR = 205°

1] The major arc CA = 255°

2] The minor arc AB = 90°

Step-by-step explanation:

In a circle:

The measure of an central angle is equal to the measure of its subtended arc
The measure of a circle is 360°
Any chord divides a circle into two arcs, a minor arc its measure is < 180° and a major arc its measure is > 180°, the sum of the measures of the minor and major arcs is 360°
If the measures of the minor and major arcs are equal, then each arc represents a semi-circle

In circle O

∵ m∠QOR = 75°

∵ ∠QOR subtended by arc QR

- By using the 1st note above

∴ m of arc QR = m∠QOR

∴ m of arc QR = 75°

∵ m∠ROS = 25°

∵ ∠ROS subtended by arc RS

∴ m of arc RS = m∠ROS

∴ m of arc RS = 25°

The measure of arc QRS is the sum of the measures of arcs QR and RS

∴ m arc QRS = 75° + 25° = 100°

∵ m∠SOT = 155°

∵ ∠SOT subtended by arc ST

∴ m of arc ST = m∠SOT

∴ m of arc ST = 155°

The measure of arc QRT is the sum of the measures of arcs QR, RS and ST

∴ m arc QRT = 75° + 25° + 155 °= 255°

∵ m∠UOT = 25°

∵ ∠UOT subtended by arc UT

∴ m of arc UT = m∠UOT

∴ m of arc RUT = 25°

The measure of arc UTS is the sum of the measures of arcs UT and TS

∴ m arc UTS = 25° + 155° = 180°

The measure of arc UTR is the sum of the measures of arcs UT, TS and SR

∴ m arc UTR = 25° + 155° + 25 = 205°

∵ The sum of the measures of the minor and major arcs is 360°

∵ m of minor arc AC = 105°

- Subtract 105 from 360° to find the measure of the major arc CA

∴ m of major arc CA = 360° - 105°

∴ m of major arc CA = 255°

∵ m of major arc AB = 270°

- Subtract 270° from 360° to find the measure of the minor arc AB

∴ m of minor arc AB = 360° - 270°

∴ m of minor arc AB = 90°

8 0

3 years ago