Formula for the circumference of a circle:
C = 2πr (C = circumference π(pi) = 3.14..... r = radius)
You know:
r = 9 cm
π = 3.14 So substitute/plug it into the equation
C = 2πr
C = 2(3.14)(9)
C = 56.52 cm
The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
=
(-
)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -
x + 3
y = -
.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Answer is in a ph
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bit.
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Answer:
The correct answer is option D. 13
Step-by-step explanation:
From the figure we can see two matrices A and B
<u>To find the sum of a₃₂ and b₃₂</u>
From the given attached figure we get
a₃₂ means that the third row second column element in the matrix A
b₃₂ means that the third row second column element in the matrix B
a₃₂ = 4 and b₃₂ = 9
a₃₂ + b₃₂ = 4 + 9
= 13
The correct answer is option D. 13
Answer: (a-b)-(2x+y)
Step-by-step explanation: The answer for number 18. (The first pair of parentheses are optional.)