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dimaraw [331]
3 years ago
11

Which of the following sequences is correct? Multiple Choice hypothesis → theory → operational definition operational definition

→ theory → hypothesis theory → hypothesis → operational definition operational definition → hypothesis → theory
Mathematics
1 answer:
sergeinik [125]3 years ago
8 0
Well little read said....
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How do you figure out this equation?
maw [93]
Equation of a circle is (x-x1)+(y-y1)=r²
when x1 and y1 are the coordinates of the centre

So you can substitute the centre in to get (x-5)²+(y+9)²=r²

When you draw a diagram it's obvious the radius is 9

9²=81

Therefore equation is (x-5)²+(y+9)²=81

Any questions, just ask :)

6 0
3 years ago
Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
Find three consecutive even integers such that 3 times the first is 26 less than twice the sum of the last two
Dimas [21]
Let's say our first integer is "a".

how to get the next consecutive EVEN integer?  well, just add or subtract 2 from it, therefore, the second consecutive integer will be "a + 2".

and the next after that, will then be (a + 2) + 2, or "a + 4".

so those are are 3 integers, a           a + 2           a+4

notice that, from any even or odd integer, if you hop twice either forwards or backwards, you'll land on another even or odd integer respectively.

2 + 2 is 4, or 8 + 2 is 10  some even ones

3 + 2 is 5, or 13 + 2 is 15, some odd ones

\bf \stackrel{\textit{3 times the first}}{3a}~~=~~\stackrel{\textit{26 less than twice the sum of the others}}{2[~(a+2)+(a+4)~]~~~-26}
\\\\\\
3a=2[~2a+6~]-26\implies 3a=4a+12-26\implies 3a=4a-14
\\\\\\
0=a-14\implies 14=a

what are the other two consecutive integers?  well, a + 2 and a + 4.
4 0
3 years ago
Match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36}
Brums [2.3K]

1st quartile: 11

median: 38.50000

3rd quartile: 45

<h3>According to the given information:</h3>
  • Order these numbers in increasing order: 6, 7, 15, 36, 41, 43, 47, 49
  • There is a 38.5 median (it is the mean of 36 and 41 - the pair of middle entries).
  • 6,7,15,36, or the left-most half of the data, make up the sample.
  • The median of the lower half is 11, which is the first quartile (it is the mean of 7 and 15 - the pair of middle entries).
  • 41, 43, 47, and 49, which are the data points in the upper half, are to the right of the median.
  • The median of the upper half is 45 in the third quartile (it is the mean of 43 and 47 - the pair of middle entries).
  • The biggest value deviates 10.5 from the median (49-38.5)

Measure descriptive statistics

1st quartile: 11

median: 38.50000

3rd quartile: 45

To know more about quartile visit:

brainly.com/question/8737601

#SPJ4

I understand that the question you are looking for is :

2 Drag the tiles to the boxes to form correct pairs. Match the values associated with this data set to their correct descriptions.  {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5  median 11  third quartile 10.5 the difference of the largest value and the median 45

7 0
2 years ago
Use the factor theorem to determine if (x-2) and (x+4) are factors of f(x)=x^3-6x^2+11x-6
Sergio [31]
Hope this can help.
I think x-2 is factor of f(x) but x+4 is not.

7 0
3 years ago
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