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dimaraw [331]
3 years ago
11

Which of the following sequences is correct? Multiple Choice hypothesis → theory → operational definition operational definition

→ theory → hypothesis theory → hypothesis → operational definition operational definition → hypothesis → theory
Mathematics
1 answer:
sergeinik [125]3 years ago
8 0
Well little read said....
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A fourth-order polynomial passes through the five points for which the independent and dependent variables, x and y, respectivel
Sladkaya [172]

Answer:

The fourth-order polynomial that passes through the points is P(x)=2x^4+x^3+3x^2+2x+5

Step-by-step explanation:

A fourth-order polynomial has this general form:

P(x)=ax^4+bx^3+cx^2+dx+e

We need to replace the given points one by one, which leads to a system of 5 equations and 5 variables (namely a,b,c,d,e)

37=a(-2)^4+b(-2)^3+c(-2)^2+d(-2)+e\\7=a(-1)^4+b(-1)^3+c(-1)^2+d(-1)+e\\5=a(0)^4+b(0)^3+c(0)^2+d(0)+e\\13=a(1)^4+b(1)^3+c(1)^2+d(1)+e\\61=a(2)^4+b(2)^3+c(2)^2+d(2)+e

We can rewrite this system as follows:

16a-8b+4c-2d+e=37\\a-b+c-d+e=7\\e=5\\a+b+c+d+e=13\\16a+8b+4c+2d+e=61

We can use the Gaussian Elimination to solve this system of equations. To use the Gaussian Elimination we need to express the system of linear equations in matrix form (the matrix equation Ax = b).

The coefficient matrix (A) for the above system is

\left[\begin{array}{ccccc}16&-8&4&-2&1\\1&-1&1&-1&1\\0&0&0&0&1\\1&1&1&1&1\\16&8&4&2&1\end{array}\right]

the variable matrix (x) is

\left[\begin{array}{c}a&b&c&d&e\end{array}\right]

and the constant matrix (b) is

\left[\begin{array}{c}37&7&5&13&61\end{array}\right]

The augmented matrix for this system, it is obtained by appending the columns of the coefficient matrix and the constant matrix.

\left[\begin{array}{ccccc|c}16&-8&4&-2&1&37\\1&-1&1&-1&1&7\\0&0&0&0&1&5\\1&1&1&1&1&13\\16&8&4&2&1&61\end{array}\right]

The augmented matrix can be transformed by a sequence of elementary row operations to the reduced row echelon form.

\left[\begin{array}{ccccc|c}1&0&0&0&0&2\\0&1&0&0&0&1\\0&0&1&0&0&3\\0&0&0&1&0&2\\0&0&0&0&1&5\end{array}\right]

Therefore the solutions are:

\left\begin{array}{c}a=2&b=1&c=3&d=2&e=5\end{array}\right

And the polynomial P(x) is:

P(x)=2x^4+x^3+3x^2+2x+5

We can check our solution plotting the polynomial and checking that it passes through the points.

4 0
3 years ago
Determine if the side lengths 6, 11, and 19 form a triangle. If it is a triangle, classify it by its sides. It's not a triangle.
Leokris [45]
Its a scalene triangle if it is a triangle
3 0
3 years ago
Read 2 more answers
For the function y=-1+6cos(2pi/7(x-5)) what is the minimum value?
s344n2d4d5 [400]

Answer:

The minimum value of y is -7

Step-by-step explanation:

Given: y=-1+6\cos(\dfrac{2\pi}{7}(x-5))

We are given a cosine function.

We need to find minimum value of function.

y=-1+6\cos(\dfrac{2\pi}{7}(x-5))

Here y is depends on cosine function.

y is minimum when cosine is minimum because y is directly proportional to cosine function.

Minimum value of cos x is -1

Therefore, For minium value of y

\cos(\dfrac{2\pi}{7}(x-5))=-1

Minimum value of y

y=-1+6(-1)

y=-7

Hence, The minimum value of y is -7

7 0
4 years ago
How long will it take Karen to drive 975 miles, if her average speed is 65 miles per hour? how to write a formula
kotykmax [81]

time = miles divided by speed

t = time

t = 975 miles / 65 mph

975/65 = 15 hours

6 0
3 years ago
Which has a positive value in Quadrant IV?
denis23 [38]
Cosine is positive in Quadrant IV.
7 0
3 years ago
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