Well, let's see . . .
You said that (a) men can dig (c) holes in (b) hours.
So . . . It takes (a) men (b / c) hours to dig one hole.
And . . . It takes One man (a b / c) hours to dig one hole.
Now . . . There are (b) holes to be dug.
It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.
But if you had 'x' men, it would only take them (c) hours to do it.
So c = (a b² / c) / x
x c = (a b² / c)
x = a b² / c² men .
Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !
Answer:
the real part is 80
the imaginary part is -60
Step-by-step explanation:
Answer:
11
Step-by-step explanation:
Replace the variable xx with −1-1 in the expression.
f(−1)=−3⋅−1+8f(-1)=-3⋅-1+8
Simplify the result.
Tap for fewer steps...
Multiply −3-3 by −1-1.
f(−1)=3+8f(-1)=3+8
Add 33 and 88.
f(−1)=11f(-1)=11
The final answer is 1111.
=11
I want brainless pleased
