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3 years ago

X² + 4x – 32x2 + x - 20

Mathematics

1 answer:

anygoal [31]3 years ago

8 0

Answer:

1. (x+8)(x-4)

2. 3x-20

Step-by-step explanation:

1. x² + 4x – 32

x² + 8x - 4x - 32

x (x+8) - 4 (x+8)

one of the x+8's is cancelled out then you have (x+8)(x-4)

2. x2 + x - 20

2x+x-20

3x-20

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How many ounces are in 8 cups

Olenka [21]

First ask your self how many ounces are in 1 cup?
8 ounces
So to find how many ounces are in 8 cups, you have to multiply how many ounces in one cyp (8) by 8
8×8=64
64 ounces

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3 years ago

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Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

Setler [38]

Both lines are parallel, since they have the same slope of 2.

8 0

3 years ago

Winston drove 70 mph. If he drives for 3.5 hours how many miles will Winston drive?

Fofino [41]

This problem can be solved using two equations:
The first represents the total trip, which is the miles driven in the morning added to those in the afternoon. Let's call the hours driven in the morning X and the hours driven in the afternoon Y. We get: X + Y = 248.
The second equation relates the miles driven in the morning compared to the afternoon. Since 70 fewer miles were driven in the morning than the afternoon, then X = Y - 70.
Now substitute the equation for morning hours (equation 2) into the total miles equation (equation 1). We get:
(Y - 70) + Y = 248
2Y - 70 = 248
2Y = 318
Y = 159
We know that Winston drove 159 miles in the afternoon.

To find the morning hours, just substitute 159 into the equation for morning hours (equation 2)
X = 159 - 70
X = 89
We now know that Winston drove 89 miles in the morning.

We can check our work by plugging both distances into the total distance equation: 89 + 159 = 248

7 0

1 year ago

A country's population in 1991 was 114 million. In 1997 it was 120 million. Estimate the population in 2014 using exponential gr

Rufina [12.5K]

The answer is 138 million.

Step 1. Calculate the growth rate.
Step 2. Calculate the population number in 2014.

We will use the formula for exponential growth:
A = P * eⁿˣ
where:
A - the final amount (value)
P - the initial amount (value)
e - the mathematical constant (e ≈ 2.72)
n - the growth rate
x - the time

Step 1:
A = 120 million = 120 000 000
P = 114 million = 114 000 000
n = ?
x = 1997 - 1991 = 6
Therefore:
$120 000 000 = 114 000 000 * e ^{n*6} \\ e ^{n*6} =120 000 000 /114000000 \\ e ^{n*6} =1.05 \\$
Logarithm both sides of the equation:
$ln(e ^{n*6})=ln(1.05) \\ n*6*ln(e) = ln(1.05) \\ 6n=ln(1.05) \\ n = \frac{ln(1.05)}{6} \\ n = \frac{0.05}{6} \\ n = 0.0083$

Step 2:
Now when we know the growth rate, it is easy to estimate the population in 2014
A = ?
P = 120 000 000
n = 0.0083
t = 2014 - 1997 = 17
$A = 120 000 000 * e ^{0.0083*17} \\ 
A = 120 000 000 * e^{0.1411} \\ 
A = 120 000 000 * 1.15 \\ 
A = 138 000 000
$
Thus, the population will be 138 million in 2014

8 0

3 years ago

Which expression is equivalent to (p^10r^−5)^1/5 ?

meriva

Answer:

p^2/r

Step-by-step explanation:

An equivalent expression is the expression in simplest form. Here apply exponent rules by multiplying the exponents of each term by 1/5.

$(p^{10}r^{-5})^{\frac{1}{5}}\\\\(p^{\frac{10}{5}}r^{\frac{-5}{5}})\\\\p^2r^{-1}\\\\\frac{p^2}{r}$

3 0

3 years ago

X² + 4x – 32x2 + x - 20​

X² + 4x – 32x2 + x - 20