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german
3 years ago
14

(cos θ + cos θ)2 + (cos θ + cos θ)2

Mathematics
1 answer:
lys-0071 [83]3 years ago
8 0
\bf [cos(\theta)+cos(\theta)]^2+[cos(\theta)+cos(\theta)]^2\implies [2cos(\theta)]^2+[2cos(\theta)]^2
\\\\\\
2^2[cos(\theta)]^2+2^2[cos(\theta)]^2\implies 4[cos(\theta)]^2+4[cos(\theta)]^2
\\\\\\
8[cos(\theta)]^2\iff 8cos^2(\theta)
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