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2 years ago

(cos θ + cos θ)2 + (cos θ + cos θ)2

1 answer:

8 0

$\bf [cos(\theta)+cos(\theta)]^2+[cos(\theta)+cos(\theta)]^2\implies [2cos(\theta)]^2+[2cos(\theta)]^2
\\\\\\
2^2[cos(\theta)]^2+2^2[cos(\theta)]^2\implies 4[cos(\theta)]^2+4[cos(\theta)]^2
\\\\\\
8[cos(\theta)]^2\iff 8cos^2(\theta)$

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Need some help with this please!!

beks73 [17]

Answer:

B,C and B,A

Step-by-step explanation:

Line the cordients and go up right,Then left to find your answer.

4 0

2 years ago

Simplify log(16x²) ± 2㏒(1÷×)

sp2606 [1]

Answer: just simplify condense it then your answer will be log(16)

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2 years ago

Please help with the question in the picture!

Stella [2.4K]

Answer:

Tan C = 3/4

Step-by-step explanation:

Given-

∠ A = 90°, sin C = 3 / 5

METHOD - I

Sin² C + Cos² C = 1

Cos² C = 1 - Sin² C

Cos² C = $1 - \frac{9}{25}$

Cos² C = $\frac{25 - 9}{25}$

Cos² C = $\frac{16}{25}$

Cos C = $\sqrt{\frac{16}{25} }$

Cos C = $\frac{4}{5}$

As we know that

Tan C = $\frac{Sin C}{Cos C }$

Tan C = $\frac{\frac{3}{5} }{\frac{4}{5} }$

Tan C = $\frac{3}{4}$ 

METHOD - II

Given Sin C = $\frac{3}{5} = \frac{Height}{Hypotenuse}$

therefore,

AB ( Height ) = 3; BC ( Hypotenuse) = 5

∵ ΔABC is Right triangle.

∴ By Pythagorean Theorem-

AB² + AC² = BC²

AC² = BC² - AB²

AC² = 5² - 3²

AC² = 25 - 9

AC² = 16

AC ( Base) = 4

Since,

Tan C = $\frac{Height}{Base}$ 

Tan C = $\frac{AB}{AC}$

Hence Tan C = $\frac{3}{4}$ 

4 0

2 years ago

A class at Middlebury school collected date on the types of movies students prefer. Complete each statement using the table.

likoan [24]

Based on the information of the table, you have:

1. The ratio is 105/150. By simplifying you get for the ratio 7/10.

2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:

165/420 = 11/28

3. The fraction of seventh graders students that prefer action movies is:

75/180 = 5/12

4. The percent of student that prefer comedy is:

105 + 150 = 255 total student that prefer comedy

420 total number of students

the fraction is:

(x/100)420 = 255

solve for x:

x = 255(100/420)

x = 60.71

the percent of students is 60.71%

5. The percent of eighth graders student who prefer action moveis is:

(x/100)240 = 90

x = 90(100/240)

x = 37.5

the percent of students is 37.5%

6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:

(x/100)180 = 75

x = 75(100/180)

x = 41.66

the percent of student is 41.66%

then, seventh grade has the greatest percent of student that prefer action movies.

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5 months ago

a man buys a dozen cameras for $1800. He sells them at a profit of $36 each. Express his profit as a percentage of his selling p

Helga [31]

First of all, we need to deduce the price of a single camera:

$\dfrac{1800}{12}=150$