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prohojiy [21]
3 years ago
5

Which two integers is √89 between

Mathematics
1 answer:
jek_recluse [69]3 years ago
8 0
9 and 10 are the integers
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How is 60 divided by 9 = 6.66666667?
saveliy_v [14]
60/9=6 remainder 4
Some division problems that require decimals
can be repeated 
To simplify 6.6666667 also means 6.666666666...and so on
To simplify 6.6666...
u put a bar over the 6 in the tens place.


7 0
4 years ago
Help pls take your time..
Nana76 [90]

Answer:

As  {x \to \infty}, \,\,{f(x) \to -\infty  and as  {x \to -\infty}, \,\,{f(x) \to \infty

Step-by-step explanation:

Please look at the plotted points in the attached image. There we see that as x grows toward infinity (to the right), the values for f(x) seem to become more negative (so f(x) seems to go towards  minus infinity).

As we move towards the left with values of x (x going towards negative infinity, f(x) seems to become more and more positive (grow toward infinity)

5 0
4 years ago
A table is on sale for $481, which is 26% less than the regular price.
bearhunter [10]

Answer: 606.06

Step-by-step explanation:

First u multiply 481×26%=125.06. Then you add 125.06 to 481 equaling 606.06 as your final answer.

6 0
3 years ago
Read 2 more answers
Which is the graph of p(x)=x^3+3x^2-16+12
ivanzaharov [21]

Answer:

wheres the answers/graphs?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
i need help with this equation please there are two more possible answers that were cut off they are 17,2% and 19,5%
Margarita [4]

Consider that the experimental probability of an event is based upon the previous trials and observations of the experiment.

The experimental probability of occurrence of an event is given by,

\text{Probability of an event}=\frac{\text{ Number of outcomes that favoured the event}}{\text{ Total number of trials or outcomes}}

As per the problem, there are a total of 1230 trials of rolling a dice.

And the favourable event is getting a 2.

The corresponding experimental probability is calculated as,

\begin{gathered} P(\text{ getting a 2})=\frac{\text{ No. of times 2 occurred}}{\text{ Total no. of times the dice is thrown}} \\ P(\text{ getting a 2})=\frac{172}{1230} \\ P(\text{ getting a 2})\approx0.13984 \\ P(\text{ getting a 2})\approx13.98\text{ percent} \end{gathered}

Thus, the required probability is 13.98% approximately.

Theref

7 0
1 year ago
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