Answer: 7 ft/sec
Step-by-step explanation:
To find the speed in feet per second, we divide distance by time.
=392/56= 7
Carter rode his bike at 7 ft/sec
Answer:
BC = 3.6
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
1.5 BC = 5.4 ( divide both sides by 1.5 )
BC = 3.6
Answer:
The speed of the bus is 74.242 kilometers per hour.
Step-by-step explanation:
Let suppose that bus runs at constant speed and that speed is measured in kilometers per hour. Then, the speed of the bus (
), in kiometers per hour, is determined by following kinematic expression:
(1)
Where:
- Travelled distance, in kilometers.
- Time, in hours.
If we know that
and
, then the speed of the bus is:


The speed of the bus is 74.242 kilometers per hour.
1/6 bc they all have an equal chance to be all the numbers on the die and their is only 6 numbers on the die so you have 1:6 probability of it being 3
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
_____
<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.