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3 years ago

A car traveled 130 miles in 2 hours. How fast did the car travel?

Mathematics

2 answers:

kifflom [539]3 years ago

7 0

You will have to divide which would be....(hold on calculating)65!
There you go your welcome

Schach [20]3 years ago

5 0

it traveled 65 miles per hour.

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Andre45 [30]

A)(2x+48x)-7 (6x•9x)+32

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2 years ago

Read 2 more answers

In the data set below, what is the interquartile range? 7 1 5 5 9 Submit

Marizza181 [45]

Answer:

Step-by-step explanation:

The interquartile range is the difference between the upper quartile and the lower quartile.

First find the median.

The median is the middle value of the data set arranged in ascending order

1 5 5 7 9 ← data in ascending order

↑ median

The lower quartile is the middle value of the data to the left of the median. If there is not an exact middle then it the average of the values on either side of the middle.

1 5

↑ lower quartile = $\frac{1+5}{2}$ = 3

The upper quartile is the middle value of the data to the right of the median.

7 9

↑ upper quartile = $\frac{7+9}{2}$ = 8

Thus

interquartile range = 8 - 3 = 5

3 0

2 years ago

ann is grouping 38 rocks, she can put into groups of 10 rocks or as single rocks what are the different ways she can group them

inysia [295]

Since Anna is either grouping them as single rock or as group of 10, we need to find the maximum number of groups of 10 as follows: 38/10 = 3.8

This means that Anna can make maximum 3 groups of 10 rocks.

Based on this, the different ways to group the rocks are as follows:
- 3 groups of 10 and 8 (which are calculated as: 38-30) single rocks
- 2 groups of 10 and 18 (which are calculated as: 38-20) single rocks
- 1 group of 10 and 28 (which are calculated as: 38-10) single rocks
- 0 group of 10 and 38 (which are calculated as: 38-0) single rocks

5 0

3 years ago

A quadrilateral has vertices at A(-5,5), B(1,8), C(4,2), and D(-2,-2). Use slope to determine if the quadrilateral is a rectangl

AysviL [449]

Answer:

The quadrilateral is not a rectangle

Step-by-step explanation:

we know that

If a quadrilateral ABCD is a rectangle

then

Opposite sides are congruent and parallel and adjacent sides are perpendicular

Remember that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

A(-5,5), B(1,8), C(4,2), and D(-2,-2)

Plot the figure to better understand the problem

see the attached figure

Find the slope of the four sides and then compare

step 1

Find slope AB

A(-5,5), B(1,8)

substitute in the formula

$m=\frac{8-5}{1+5}$

$m=\frac{3}{6}$

$m_A_B=\frac{1}{2}$

step 2

Find slope BC

B(1,8), C(4,2)

substitute in the formula

$m=\frac{2-8}{4-1}$

$m=\frac{-6}{3}$

$m_B_C=-2$

step 3

Find slope CD

C(4,2), and D(-2,-2)

substitute in the formula

$m=\frac{-2-2}{-2-4}$

$m=\frac{-4}{-6}$

$m_C_D=\frac{2}{3}$

step 4

Find slope AD

A(-5,5), D(-2,-2)

substitute in the formula

$m=\frac{-2-5}{-2+5}$

$m=\frac{-7}{3}$

$m_A_D=-\frac{7}{3}$

step 5

Verify if the opposites are parallel

Remember that

If two lines are parallel, then their slopes are the same

The opposite sides are

AB and CD

BC and AD

we have

$m_A_B=\frac{1}{2}$

$m_C_D=\frac{2}{3}$

$m_A_B \neq m_C_D$

It is not necessary to continue verifying, because two of the opposite sides are not parallel

therefore

The quadrilateral is not a rectangle

4 0

3 years ago

Is 3/8bigger than 4/10

mojhsa [17]

The way to work this out is to find a common denominator. so in this case 80 is a common denominator. So it would be 3/8 into 30/80 and then 4/10 into 32/80 therefore 4/10 is bigger

7 0

3 years ago