Convert 3 kilograms to ounces

The ratio of adults to children on a train in 7:2. There are 245 adults on the train. Find the total number of people on the tra

Kruka [31]

Answer:

315 people

Step-by-step explanation:

Using the given ratio, we can figure out the number of children on the train by doing cross multiplication.

Let x = # of children on train.

7/2 = 245/x

7x = 490

x = 70 children

The total number of people = 70 + 245 = 315 people total

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5 0

3 years ago

If in an equation the variables cancel out while solving and u are left with a true statement how many solutions are there and i

Deffense [45]

Answer: infinitely many and none

Step-by-step explanation:

if all variables cancel and you are left with zero, there are infinitely many solutions. if it is false there are no solutions.

4 0

3 years ago

Read 2 more answers

Y=x-4 y=4x+2<br> whats the solution of system equations

Fittoniya [83]

Answer:

X=-2

Y=-6

Step-by-step explanation:

Since both equations are already expressed in the simplest form of y, then we equate them to be equal hence

x-4=4x+2

Bringing like terms together

-4-2=4x-x

Solving both sides

-6=3x

Making x the subject then

X=-6/3=-2

Subsrituting the value of x into any of the initial equations

Y=x-4 then y=-2-4=-6

Therefore, the solution is

X=-2

Y=-6

6 0

3 years ago

Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that $p = 0.95$

10 targets

This means that $n = 10$

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

$P(X = 10) + P(X < 10) = 1$

We want P(X < 10). So

$P(X < 10) = 1 - P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987$

$P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401$

40.1% probability that he will miss at least one of them

7 0

3 years ago

a school sells boxes of cookies each year for a charity fund .the data set shows the number of boxes the 10 families living on w

Thepotemich [5.8K]

0, 1, 1, 2, 2, 2, 2, 3, 3, 5

minimum: 0
maximum: 5
mean: 2.1
median: 2
mode: 2

I think the data have zero skew. Its mean, median, and mode are based on 2. It shows symmetry.

8 0

3 years ago