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mart [117]
4 years ago
5

What is the inverse of the functionf(x)=2x+1

Mathematics
2 answers:
MrRissso [65]4 years ago
6 0

Solution :

Given , functionf(x) = 2x+1

we have to find the inverse of the function f(x)

Substitute y for f(x):  y=2x+1

Subtract 1 from both sides, y-1=2x+1-1

Divide both sides by 2, \frac{y-1}{2} = x

\Rightarrow x=\frac{y-1}{2}

Substitute f^{-1}(y)\:for\:x\RIghtarrow f^{-1}(y)=\frac{y-1}{2}

Hence, The inverse of the function f(x)=2x+1\:is f^{-1}(y)=\frac{y-1}{2}

mr Goodwill [35]4 years ago
3 0

x = 2x + 1

x - 2x = 1

-x = 1

x = -1

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After solving 3(5y - 4) + 31 - 3y = 3(2y - 3) the value of y is y=-\frac{14}{3}\,\,or\,\,y= -4.66

Step-by-step explanation:

We need to solve the expression:

3(5y - 4) + 31 - 3y = 3(2y - 3)

and find the value of y

Solving:

3(5y - 4) + 31 - 3y = 3(2y - 3)\\15y-12+31-3y=6y-9\\Combining\,\,like\,\,terms:\\15y-3y-6y=-9+12-31\\15y-9y=12-40\\6y=-28\\y=-\frac{28}{6}\\y=-\frac{14}{3}\\or\,\,y= -4.66

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