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Georgia [21]
3 years ago
12

Help please anyone! Brainliest reward it counting on it!

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
X1 + x2  / 2 , y1 + y2 / 2

8 + x2 /2 = 6

So x  is 4

9 + y2 /2 = 6

So y is 3.

Answer is B ( 4, 3)

Please Mark Brainliest if it helped
You might be interested in
The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the
navik [9.2K]

Answer:

a) 0.019

b) 0.563

c) x = 1.966 hours

Step-by-step explanation:

E(X) = 1

Exponential random variable's probability function is given as

P(X=x) = λ e^(-λ.x)

The cumulative distribution function is given as

P(X ≤ x) = 1 - e^(-λ.x)

a) The time between the arrivals of small aircraft at a county airport that is exponentially distributed.

But the number of planes that land every hour will be obtained using the Poisson distribution formula.

It is the best for discrete systems.

Poisson distribution formula is given as

P(X = x) = (e^-λ)(λˣ)/x!

λ = 1 aircraft per hour.

The probability that more than three aircraft arrive within an hour = P(X > 3)

P(X > 3) = 1 - P(X ≤ 3) = 1 - [P(X=0) + P(X=1) + P(X=2) + P(X=3)]

P(X > 3) = 1 - 0.98101 = 0.01899 = 0.019 to 3 d.p

b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals

Probability of one 1-hour interval not containing more than 3 arrivals = 1 - P(X > 3)

= 1 - 0.01899 = 0.98101

Probability that thirty 1-hour intervals will not contain more than 3 arrivals = (0.98101)³⁰ = 0.5626 = 0.563 to 3 d.p

c) Determine the length of an interval of time (In hours) such that the probability that no arrivals occur during the interval is 0.14

We can now use the cumulative distribution function for exponential random variable for this

P(X ≤ x) = 1 - e^(-λ.x)

P(X > x) = 1 - P(X ≤ x)

P(X > x) = e^(-λ.x)

λ = 1, x = ?,

0.14 = e⁻ˣ

e⁻ˣ = 0.14

In e⁻ˣ = In 0.14 = -1.966

-x = -1.966

x = 1.966 hours

Hope this Helps!!!

4 0
3 years ago
17+5 plz show communitive property
wariber [46]

Answer:

17+5=17+5

No matter what order you put them it will always be the same

5 0
3 years ago
Read 2 more answers
Please help me answer this !!!
OLga [1]
Need more information

8 0
3 years ago
En la escuela Francisco I. Madero de ciudad Delicias, llevaron a cabo el festejo para
REY [17]

Answer:

The number of unsold cakes was 2

Step-by-step explanation:

<u><em>The question in English is</em></u>

In the school Francisco I. Madero of Ciudad Delicias, the celebration was held for  commemorate the arrival of spring, after the parade the stalls were set up  of the kermesse. The first grade group bought 8 cakes and sold 3/4 of the total.

How much of the cake was not sold?

Let

x ----> number of cakes sold

y ----> number of cakes that didn't sell

we know that

The first grade group bought 8 cakes

so

x+y=8 -----> equation A

The first grade group sold 3/4 of the total.

so

x=\frac{3}{4}(x+y) ---> equation B

substitute equation A in equation B

x=\frac{3}{4}(8)=6

Find the value of y

6+y=8

y=2

therefore

The number of unsold cakes was 2

4 0
3 years ago
See attached image. For part b, my answer is <img src="https://tex.z-dn.net/?f=h%28t%29%3D%5Cfrac%7Bt%5E2%7D%7B100%7D-%5Cfrac%7B
ArbitrLikvidat [17]

Answer:

a) shown

b) h = [sqrt(17) - (5/2)t]²

c) t = 2sqrt(17)/5 seconds

Step-by-step explanation:

V = pi × r² × h

V = pi × 5² × h

V = 25pi × h

a) dV/dt = dV/dh × dh/dt

-5pi × sqrt(h) = 25pi × dh/dt

dh/dt = -sqrt(h)/5

b) 1/sqrt(h) .dh = -5. dt

2sqrt(h) = -5t + c

t = 0, h = 17

2sqrt(17) = 0 + c

c = 2sqrt(17)

2sqrt(h) = -5t + 2sqrt(17)

sqrt(h) = [2sqrt(17) - 5t] ÷ 2

sqrt(h) = sqrt(17) - (5/2)t

Square both sides

h = [sqrt(17) - (5/2)t]²

c) empty: h = 0

0 = [sqrt(17) - (5/2)t]²

sqrt(17) - (5/2)t = 0

(5/2)t = sqrt(17)

t = 2sqrt(17)/5

t = 1.64924225 seconds

sqrt: square root

5 0
4 years ago
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