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Georgia [21]
3 years ago
12

Help please anyone! Brainliest reward it counting on it!

Mathematics
1 answer:
Viefleur [7K]3 years ago
4 0
X1 + x2  / 2 , y1 + y2 / 2

8 + x2 /2 = 6

So x  is 4

9 + y2 /2 = 6

So y is 3.

Answer is B ( 4, 3)

Please Mark Brainliest if it helped
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Hey guys happy Tuesday ! I need some home work help ASAP work and answer pls love y’all ❤️
Strike441 [17]
1. Multiply 5 by 2 since the piece is twice as long. That is 10. 
Multiply 4 by 3 since the piece is 3 times as long. That is 12. 
Her piece is 10 x 12. 
2 sides of 10 & 2 sides of 12.
Multiply 10 & 12 by 2 to get 20 and 24. Add them together to get 44 inches, which is the perimeter. 

2. Multiply 4 x 2 since length is twice width. That is 8. 
Multiply 8 x 4 to get the area of the red paper. That is 32. 
Multiply 3 x 7 to get the area of the blue paper. That is 21.
Subtract 21 from 32 to get the amount of red paper that wasn't covered up.
11 square cm were not covered up. 

Hope this helps!
8 0
2 years ago
What is the surface area of the following rectangular prism? Express your answer in square millimeters.
Black_prince [1.1K]

Answer:

28,800

Step-by-step explanation:

thats the answer

8 0
3 years ago
Read 2 more answers
What is 180 inches in feet
Naya [18.7K]

Answer:15

Step-by-step explanation:

180÷12

7 0
2 years ago
Read 2 more answers
There are 154 players on 11 teams . How many players are on one team
jarptica [38.1K]

Answer:

there are 14 on a single team

Step-by-step explanation:

154÷11=14

Or you can do this

11 • 14

add 11 14 times you get 154

7 0
3 years ago
Simplify the expression below.
olasank [31]
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}
\\\\
-------------------------------\\\\

\bf \cfrac{14a^8y^3-7a^4y^5+28a^{12}y^2}{7a^4y}\impliedby 
\begin{array}{llll}
\textit{let us first, distribute}\\
the~denominator
\end{array}
\\\\\\
\cfrac{14a^8y^3}{7a^4y}-\cfrac{7a^4y^5}{7a^4y}+\cfrac{28a^{12}y^2}{7a^4y}
\\\\\\
\cfrac{14}{7}a^8a^{-4}y^{-1} y^3-\cfrac{7}{7}a^4a^{-4}y^{-1} y^5+\cfrac{28}{7}a^{12}a^{-4}y^{-1} y^2
\\\\\\
2a^{8-4}y^{-1+3}-1a^{4-4}y^{-1+5}+4a^{12-4}y^{-1+2}
\\\\\\
2a^4y^2-1\cdot 1y^4+4a^8y\implies 2a^4y^2-y^4+4a^8y
4 0
2 years ago
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