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geniusboy [140]
2 years ago
10

Given h(x) = x2 – 5x + 7, find the following. a. h(2) b.h(-5) c. h(-8)

Mathematics
1 answer:
azamat2 years ago
5 0

Answer:

Step-by-step explanation:

hello :

h(x) = x² – 5x + 7

h(-2) = (-2)² – 5(-2) + 7 =4+10+7 =21

h(-5) = (-5)² – 5(-5) + 7= 25+25+7 =57

h(-8) = (-8)² – 5(-8) + 7 = 64+40+7=111

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Answer:

The answer is

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Step-by-step explanation:

If two equations are parallel it means that both their gradients are equal. We were given the equation:

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in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:

5x + 2y = 12 \\ 2y = 12 - 5x \\  \frac{2y}{2}  =  \frac{12}{2}  -  \frac{5}{2} x \\ y = 6  -  \frac{5}{2} x \: \\ or \: \\ y =   - \frac{5}{2} x + 6

Therefore the gradient of the parallel line with points (-2, 4) is also -5/2

y = mx + c \\ 4 =  - \frac{ 5}{2} ( - 2) + c \\ 4 =  \frac{10}{2}   + c \\ 4 = 5 + c \\ 4 - 5 = c \\

c =  - 1 \\ hence \: the \: equation \: for \: the \: \\  parallel \: line \: is \\  \: y =  -  \frac{5}{2} x  - 1

8 0
2 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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