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3 years ago

If a room is 22W and 12 L, WHAT is ratio of the length of room to its area

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Area = 22 x 12 = 264

The ratio of the length of room to its area = 12 / 264 = 1/22

Answer

The ratio of the length of room to its area = 1/22 or 1 : 22

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F(x)=2x^2-x+1 find the vertex

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The Answer fam is (1/4,7/8)

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3 years ago

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

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3 years ago

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Answer:

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3 years ago

Read 2 more answers

4. A drawing of the top of a desk iS shown.

KATRIN_1 [288]

The area of the top of a desk which is shown and the dimensions of the top is 5 feet and 2 feet, is 10 squared feet.

<h3>What is the area of a rectangle?</h3>

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

$A=a\times b$

Here, (a)is the length of rectangle and (b) is the width of the rectangle

A drawing of the top of a desk is shown.

5 feet
2 feet

The image of drawing ins not given in the problem. Here, the length of the desk is 5 feet and the width of the desk is 2 feet according to the data.

$a=5\rm\; feet\\b=2\rm\; feet$