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otez555 [7]
3 years ago
10

Help me please with this question

Mathematics
1 answer:
lukranit [14]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

2B + 3C

= 2 \left[\begin{array}{ccc}4&-5\\-2&1\\\end{array}\right] + 3 \left[\begin{array}{ccc}1&-1\\-6&3\\\end{array}\right]

Multiply each element in the matrices by the scalar quantity, that is

= \left[\begin{array}{ccc}8&-10\\-4&2\\\end{array}\right] + \left[\begin{array}{ccc}3&-3\\-18&9\\\end{array}\right]

Add corresponding elements from each matrix

= \left[\begin{array}{ccc}8+3&-10-3\\-4-18&2+9\\\end{array}\right]

= \left[\begin{array}{ccc}11&-13\\-22&11\\\end{array}\right]

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Please help with this
Dafna1 [17]

Answer:

A

Step-by-step explanation:

● first one:

The diagonals of a rhombus are perpendicular to each others wich means that they form four right angles.

STP is one of them so this statement is true.

● second one:

If ST and PT were equal this would be a square not a rhombus.

● third one:

If SPQ was a right angle, this woukd be a square.

● fourth one:

Again if the diagonals SQ and PR were equal, this would be a square.

5 0
3 years ago
Whats an equation that make x=31 ? like in other words give me an equation where it leads down to 31
MrRa [10]
Sure, that's easy! Here's one

5x + 7 = 162

If I wanted to solve this equation, I would break it down. I'd subtract the result (162) by 7

162 - 7 = 155.

From there I just divide that by 5!

155 / 5 = 31

There it is! Ultimate proof that x is in fact 31!
5 0
3 years ago
Read 2 more answers
If ABC is reflected across the y-axis, what are the coordinates of A?
quester [9]

Answer:

The answer is option A

Step-by-step explanation:

Reflection in the y axis is

(x , y) → ( - x , y)

The coordinates of A are ( 2, -5)

When it's reflected in the y axis it becomes

( - 2 , - 5)

Hope this helps you

4 0
3 years ago
Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a
ddd [48]

The formula for distance is equal to:

d = v * t

where d is distance, v is velocity or speed, and t is time

 

Since the distance travelled by the two airplane is similar, therefore we can create the initial equation:

 

v1 * t1 = v2 * t2

 

We know that v1 = 496, and v2 = 558 so:

 

496 t1 = 558 t2

or

x = 558 t2 / 496

 

We also know that airplane 1 travelled 30 minutes (0.5 hours) earlier than airplane 2, therefore:

 

x = t2 + 0.5

 

Hence,

496 (t2 + 0.5) = 558 t2

496 t2 + 248 = 558 t2

t2 = 4 hours

 

x = t2 + 0.5 = 4 + 0.5

x = 4.5 hours

 

 

So the equation is:

x = 558 t2 / 496

 

And the first plane travelled:

x = 4.5 hours

5 0
3 years ago
Answer this for me guys
Andrews [41]

Answer:

Answer: 1 1/4

Step-by-step explanation:

1/4 * -5

5 0
3 years ago
Read 2 more answers
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