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Phoenix [80]
3 years ago
6

Need help on 60 please!

Mathematics
1 answer:
barxatty [35]3 years ago
3 0
Thousand=2,000
ten thousand=7,000
hundred thousand=100,072,055(i think :/ )
million(not sure) 10million?
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A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk in 3/4 hour if he walks?
Nezavi [6.7K]

Given:

Consider the complete question is "A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour. How far will he walk in 3/4 hours if he walks twice as fast?"

A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour.

To find:

Distance covered by him if in 3/4 hour if he walks twice as fast.

Solution:

We have,

Distance=4\dfrac{1}{2}=\dfrac{9}{2}

It means a speed walker covered \dfrac{9}{2} mi in \dfrac{3}{4} hour.

If the speed is twice then he can cover double distance is same time.

Distance covered by him if in 3/4 hour if he walks twice as fast is

2\times \dfrac{9}{2}=9

Therefore, distance covered by him is 9 mi.

7 0
3 years ago
While traveling at a constant speed in a car, the centrifugal acceleration passengers feel while the car is turning is inversely
kvv77 [185]

A = k/R where A = acceleration and R = radius of the turn and k is a constant to be found.

Substituting the given values:-

10 = k / 70

k = 10*70 = 700

So the equation of the motion is A = 700 / R

When the radius is 140 the acceleration is 700 / 140 = 5 ft/sec/sec ( answer)

4 0
3 years ago
At noon Joyce drove to the lake at 30 miles per hour. but she made the long walk back home at 4 miles per hour. How long did she
mars1129 [50]

Answer:

60 miles

Step-by-step explanation:

let d = distance to the lake

Using:  time = distance ÷ speed

Create expressions for the time it takes for each journey:

Drive:  t_1=\dfrac{d}{30}

Walk:   t_2=\dfrac{d}{4}

If total time = 17 hours

\implies t_1+t_2=17

\implies \dfrac{d}{30}+\dfrac{d}{4}=17

\implies \dfrac{17d}{60}=17

\implies 17d=1020

\implies d=\dfrac{1020}{17}

\implies d=60

Therefore she walked 60 miles

3 0
2 years ago
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1 The metal used to make a coin is a mixture of steel and copper. The ratio mass of steel
Masteriza [31]

\huge{ \underline{ \underline{ \gray{ \bf{Solution:}}}}}

Let,

  • Mass of the steel be 108x
  • Mass of the copper be 7x
  • Then, Total mass = 108x + 7x = 115x

Given,

  • Total mass of the coin = 230 mg

That means,

⇛ Total mass of the coin = 230 mg

⇛ 115x = 230 mg

⇛ x = 230 mg/115

⇛ x = 2 mg

Then,

  • Mass of the steel = 108(2) = 216 mg
  • Mass of the copper = 7(2) = 14 mg

☁️ ANSWER - 14 mg (Mass of copper)

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7 0
3 years ago
HELP ME OUT HERE! PLS TELL ME HOW U GOT THE ANSWER TOO!
IgorC [24]

Answer: Choice C

\begin{array}{|c|c|} \cline{1-2}x & y\\\cline{1-2}0 & 1\\\cline{1-2}2 & 2\\\cline{1-2}4 & 3\\\cline{1-2}6 & 4\\\cline{1-2}\end{array}

=========================================================

Explanation:

There are four marked points on the line.

Each point is of the form (x,y)

  • The first or left most point is (0,1)
  • The second point is (2,2)
  • The third is (4,3)
  • The fourth is (6,4)

Each of these points is then listed in the table format as shown above.

There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).

Extra side notes:

  • The slope of this line is m = 1/2 = 0.5
  • The y intercept is 1 located at (0,1)
  • The equation of this line is y = 0.5x+1
8 0
2 years ago
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