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il63 [147K]
3 years ago
13

Kayla is blowing up balloons for her sister’s birthday party. She tries to blow up each balloon to a maximum diameter of 5 inche

s. At that diameter, the volume of each balloon is about 26 cubic inches. Find the independent and dependent variable in words for examples like Height in inches or something similar.
Mathematics
1 answer:
ale4655 [162]3 years ago
8 0

Answer: Independent variable = diameter of balloon

Dependent variable = Volume

Step-by-step explanation:

Definitions:

  • Independent variable : Variable that can be manipulated to see the effect in the response variable in a study.
  • Dependent variable : Response variable which depends on the independent variable.

Here, diameter of balloon = Independent variable

and Volume = Dependent variable

Because volume can change with the change of diameter of the balloon.

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Solve for X. X/8 = 3 3/4 <br> A. 30 <br> B. 24 3/4 <br> C.120 <br> D.15/32
Feliz [49]
X / 8 = 3.75
X = 3.75 * 8
X = 30
6 0
3 years ago
A right circular cone of radius 6 inches, side length of 16 inches and height of h inches. Which is closest to the height of a c
Elis [28]

Answer:

Height of cone (h) = 14.8 in (Approx)

Step-by-step explanation:

Given:

Radius of cone (r) = 6 in

Slant height (l) = 16 in

Find:

Height of cone (h) = ?

Computation:

Height of cone (h) = √ l² - r²

Height of cone (h) = √ 16² - 6²

Height of cone (h) = √ 256 - 36

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Height of cone (h) = 14.8 in (Approx)

8 0
3 years ago
What is the domain of the square root function graphed below?
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The domain of a function is the set of all values x can have.
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The domain is

x \ge 3
5 0
4 years ago
Help me i need to submit to my teacher by 8pm​
Vladimir [108]

Please see the figure. We'll first work out half the area of the rounded triangle, half the unshaded part, then double it, then subtract it from the big square.

Half the area is the circular sector PTQ (with center P, arc TQ) minus the right triangle PUT.

A/2 = area(sector PTQ) - area(triangle PUT)

The triangle is half of equilateral triangle PQT, so a 30/60/90 right triangle so we know the sides are in ratio 1:√3:2 so

TU = (7/2)√3

area(PUT) = (1/2) (7/2)(7/2)√3 = (49/8)√3

area(sector PTQ) = (angle TQP / 360°) πr^2

We know angle TQP is 60° because TQP is equilateral.  r=7.

area(sector PTQ) = (60°/360°) π (7²) = 49π/6

Putting it together,

A/2 = area(sector PTQ) - area(triangle PUT)

A = 2(49π/6 -  (49/8)√3)

A = 49(π/3 - √3/4) square cm

I hate ruining a nice exact answer with an approximation, but they seem to be asking.

A ≈ 30.095057615914535

Check:

I'm not sure how to check it.  I'd estimate it's about 25% bigger than equilateral triangle PQT with area (√3/4)7² ≈ 21.2, so around 27. 30 seems reasonable.

Now the real area we seek is the big square PQRS minus A, so

area = 7² - 30.095057615914535 = 18.904942384086 sq cm

They want square meters for some reason; we scale by (1/100)²

Answer: 0.00189 square meters

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Mrac [35]
The height of the tower roughly equals 41.421 meters.
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3 years ago
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