Answer:
7
4
Step-by-step explanation:
The <u>actual values</u> are shown on the given graph as <u>blue points</u>.
The <u>line of regression</u> is shown on the given graph as the <u>red line</u>.
From inspection of the graph, in the year 2000 the actual rainfall was 43 cm, shown by point (2000, 43). It appears that the regression line is at y = 50 when x is the year 2000.
⇒ Difference = 50 - 43 = 7 cm
<u>In 2000, the actual rainfall was </u><u>7</u><u> centimeters below what the model predicts</u>.
From inspection of the graph, in the year 2003 the actual rainfall was 44 cm, shown by point (2003, 40). It appears that the regression line is at y = 40 when x is the year 2003.
⇒ Difference = 44 - 40 = 4 cm
<u>In 2003, the actual rainfall was </u><u>4</u><u> centimeters above what the model predicts.</u>
Answer:
105°
Step-by-step explanation:
11x-5 + 6x+5 + x = 180
18x = 180
x = 10
m∠Q = 11(10)-5 = 110-5 = 105°
Answer:
y=-3x-5
Step-by-step explanation:
6x+2y=-10
2y = -6x-10 (you need to isolate the y and so i took 6x and subtracted it from both sides)
y = -6/2x-10/2 ( dont feel like explaining)
divide them (-6/2 and -10/2) to get
y=-3x-5
Hope i helped
