Question

1. What are the domain restrictions of q^2−7q−8/q^2+3q−4

Answer 1

(1)

we are given

$\frac{q^2-7q-8}{q^2+3q-4}$

We know that any function is undefined when denominator =0

so, we will set denominator =0

and then we can solve for q

$q^2+3q-4=0$

now, we can factor it

$(q+4)(q-1)=0$

$(q+4)=0$

$q=-4$

$(q-1)=0$

$q=1$

so,

q≠1 and q≠−4............Answer

(2)

we are given

$\frac{y^2-3y-40}{y^2+9y+20}$

Since, any function is undefined when denominator =0

so, we set denominator =0

and then we can solve for y

$y^2+9y+20=0$

$(y+4)(y+5)=0$

$(y+4)=0$

$y=-4$

$(y+5)=0$

$y=-5$

so,

y≠−5

y≠−4.............Answer