The example I would be using is the level of a see-saw and take
a point 1 /x of the way amid the middle and the left end. If you change
the point vertically by f feet, the far right finish transfers vertically
by f×−x feet. If you push down, f would be negative then you are
multiplying two negative numbers for a positive result, this means that the
other end moves up.
<span>The answers are b = 5 square root of 3; b = -5 square root of 3. f(b) = b^2 – 75. If f(b) = 0, then b^2 – 75 ) 0. b^2 = 75. b = √75. b = √(25 * 3). b = √25 * √3. b = √(5^2) * √3. Since √x is either -x or x, then √25 = √(5^2) is either -5 or 5. Therefore. b = -5√3 or b = 5√3.</span>
Answer:
Equation of line in slope-intercept form that passes through (4, -8) and is perpendicular to the graph
is below

Step-by-step explanation:
Slope of the equation
is 
Since slopes of perpendicular lines are negative reciprocal of each other, therefore slope of other line is given as

Equation of line in point slope form is given as

Here (x1, y1) = (4, -8)

Simplifying it further


the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.
the input goes to the 1st machine and the output of that goes to the 2nd machine.
a)
if she uses and input of 6 on the 2nd one, the result will be 6² - 6 = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.
b)
clearly we can never get an output of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.
let's check something, we need a -5 on the 2nd, so

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.
