Answer:
Step-by-step explanation:
Please use " ^ " to indicate exponentation: y= x^2 + 11x + 24. Thanks.
Because x^2 is positive, the graph of this parabola opens up.
We can find the vertex and roots (zeros) as follows, using the quadratic formula:
With a = 1, b = 11 and c = 24,
-11 ± √ [ (11^2-4(1)(24) ] -11 ± √25
x = ------------------------------------ = --------------- = -3 and x = -8
2(1) 2
This tells us that the x-intercepts are at (-3, 0) and (-8, 0). The minimum value is at x = -b / (2a), which here is x = -11 / [2] = -5 1/2 (which is halfway between the zeros).
The vertex (and thus, the minimum) is at (-5 1/2, f(-5 1/2) ).
