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Ket [755]
3 years ago
8

The square below represents a unit or a whole. What fraction is represented by the

Mathematics
1 answer:
Mkey [24]3 years ago
5 0
20/28 or 10/14 or 5/7
You can keep reducing until both sides of the fraction can't be divided by the same number anymore.
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(x+5)(y+10) <br><br> what is the answer to this equation?
netineya [11]
(x + 5)(y + 10)
x(y + 10) + 5(y + 10)
x(y) + x(10) + 5(y) + 5(10)
xy + 10x + 5y + 50
7 0
3 years ago
(Algebra II) Standard Form of a Quadratic Function - I'm having trouble with two questions on this quiz? Please don't just give
anastassius [24]
1.
the x value of the vertex in form
ax^2+bx+c=y
is
-b/2a
so

-2x^2+8x-18
x value of vertex is
-8/(2*-2)=-8/-4=2

plug it in to get y value
-2(2)^2+8(2)-18
-2(4)+16-18
-8-2
-10

vertex is at (2,-10)
or you could complete the square to get into y=a(x-h)^2+k, where the vertex is (h,k)
so as follows
y=(-2x^2+8x)-18
y=-2(x^2-4x)-18
y=-2(x^2-4x+4-4)-18
y=-2((x-2)^2-4)-18
y=-2(x-2)^2+8-18
y=-2(x-2)^2-10
vertex is (2,-10)






5.
vertex is the time where the speed is the highest
at about t=10, the speed is at its max
6 0
3 years ago
Read 2 more answers
What is the area?<br> 4 m<br> 7 m<br> 8 m
Ipatiy [6.2K]

Answer:

224

Step-by-step explanation:

Multiply all the numbers

4 0
3 years ago
Two cards are selected from a standard deck of 52 playing cards. The first card is not replaced before the second card is select
Blizzard [7]

Answer:

Probability is:   $ \frac{\textbf{13}}{\textbf{51}} $

Step-by-step explanation:

From a deck of 52 cards there are 26 black cards. (Spades and Clubs).

Also, there are 26 red cards. (Hearts and Diamonds).

First, we determine the probability of drawing a black card.

P(drawing a black card) = $ \frac{number \hspace{1mm} of  \hspace{1mm} black  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm} of  \hspace{1mm} cards} $  $ = \frac{26}{52} = \frac{\textbf{1}}{\textbf{2}} $

Now, since we don't replace the drawn card, there are only 51 cards.

But the number of red cards is still 26,

∴ P(drawing a red card) = $ \frac{number  \hspace{1mm} of  \hspace{1mm} red  \hspace{1mm} cards}{total  \hspace{1mm} number  \hspace{1mm}of  \hspace{1mm} cards} $  $ = \frac{26}{51}  $

Now, the probability of both black and red card = $ \frac{1}{2} \times \frac{26}{51} $

$ = \frac{\textbf{13}}{\textbf{51}} $

Hence, the answer.

5 0
3 years ago
Easy need help will mark brainliest
frosja888 [35]

Answer:

6v^3

Step-by-step explanation:

i think so. dont critisize me

8 0
3 years ago
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