1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
2 years ago
10

In the design phase of the systems development life cycle (SDLC), the _____ design is an overview of the system and does not inc

lude hardware or software choices. Group of answer choices
Computers and Technology
1 answer:
lyudmila [28]2 years ago
5 0

Answer:

"Conceptual" is the correct answer.

Explanation:

  • SDLC would be a particular implementation of a software administration that defines the processes responsible for the creation of such an organization or project, through preliminary feasibility studies to accomplished program activities.
  • The conceptual design seems to be the very first phase of the cycle of brand management, using designs as well as other diagrams or models. It offers an implementation of the study product as a result of a collection of interconnected values and principles about what it will do, function, and look in a user-friendly way.
You might be interested in
A personal academic plan is a set of goals relating to the things you want to accomplish while you are in school.
Alex787 [66]

Answer:

True

Explanation:

8 0
2 years ago
Before u can open and edit a file, you need to zip it, T/F
koban [17]

Answer

False, it is not necessary that you need to zip a file always when you are opening and editing a file

<u><em>PLS MARK BRAINLIEST</em></u>

5 0
3 years ago
Define a function UpdateTimeWindow() with parameters timeStart, timeEnd, and offsetAmount. Each parameter is of type int. The fu
NARA [144]

Answer:

Here is a UpdateTimeWindow() method with parameters timeStart, timeEnd, and offsetAmount

// the timeEnd and timeStart variables are passed by pointer

void UpdateTimeWindow(int* timeStart, int* timeEnd, int offsetAmount){

// this can also be written as  *timeStart = *timeStart + offsetAmount;

*timeStart += offsetAmount;  //adds value of offsetAmount to that of //timeStart

// this can also be written as  *timeEnd = *timeEnd + offsetAmount;

  *timeEnd += offsetAmount;  } //adds value of offsetAmount to that of //timeEnd

Explanation:

The function has three int parameters timeStart, timeEnd, and offsetAmount.

First two parameters timeStart and End are passed by pointer. You can see the asterisk sign with them. Then in the body of the function there are two statements *timeStart += offsetAmount; and *End+= offsetAmount; in these statements the offsetAmount is added to the each of the two parameters timeStart and timeEnd.

8 0
2 years ago
Hello, this is a 2 part question for my beginning assembly class. Thank you in advance for your help
madam [21]

Answer:

Complete code is given below:

Explanation:

INCLUDE Irvine32.inc

.data

msgMenu BYTE "---- Boolean Calculator ----", 0dh,0ah

BYTE 0dh,0ah

BYTE "1. x AND y"     ,0dh,0ah

BYTE "2. x OR y"      ,0dh,0ah

BYTE "3. NOT x"       ,0dh,0ah

BYTE "4. x XOR y"     ,0dh,0ah

BYTE "5. Exit program",0

msgAND      BYTE "Boolean AND",0

msgOR       BYTE "Boolean OR",0

msgNOT      BYTE "Boolean NOT",0

msgXOR      BYTE "Boolean XOR",0

msgOperand1 BYTE "Input the first 32-bit hexadecimal operand: ",0

msgOperand2 BYTE "Input the second 32-bit hexadecimal operand: ",0

msgResult   BYTE "The 32-bit hexadecimal result is:            ",0

caseTable   BYTE '1'     # lookup value

DWORD _AND_op        # address of the procedure

EntrySize = ($ - caseTable )

   BYTE '2'

   DWORD _OR_op

   BYTE '3'

   DWORD _NOT_op

   BYTE '4'

   DWORD _XOR_op

   BYTE '5'

   DWORD _ExitProgram

NumberOfEntries=($ - caseTable)/EntrySize

.code

main08stub PROC

   call Clrscr

Menu:

   mov edx, OFFSET msgMenu # menu choices

   call WriteString

   call Crlf

L1: call ReadChar

   cmp al, '5' # is selection valid (1-5)?

   ja L1   # if above 5, go back

   cmp al, '1'

   jb L1   # if below 1, go back

   call Crlf

   call **BLANK**

   jc quit # if CF = 1 exit

   call Crlf

   jmp Menu    # display menu again

quit: exit

main08stub ENDP

#----------------------------------------

**BLANK** PROC

#

# It selects a procedure from the case table

# Receives: AL = number of procedure

# Returns: nothing

#-----------------------------------

   ret

**BLANK** ENDP

#------------------------------------------------

_AND_op PROC

#

# Performs a boolean AND operation

# Receives: Nothing

# Returns: Nothing

#------------------------------------------------

   ret

_AND_op ENDP

#------------------------------------------------

_OR_op PROC

#

# Performs a boolean OR operation

# Receives: Nothing

# Returns: Nothing

#------------------------------------------------

   ret

_OR_op ENDP

#------------------------------------------------

_NOT_op PROC

#

# Performs a boolean NOT operation.

# Receives: Nothing

# Returns: Nothing

#------------------------------------------------

   ret

_NOT_op ENDP

#------------------------------------------------

_XOR_op PROC

#

#

# Performs an Exclusive-OR operation

# Receives: Nothing

# Returns: Nothing

#------------------------------------------------

   ret

_XOR_op ENDP

#------------------------------------------------

_ExitProgram PROC

#

# Receives: Nothing

# Returns: Sets CF = 1 to signal end of program

#------------------------------------------------

   ret

_ExitProgram ENDP

END main08stub

3 0
3 years ago
Which of the following is true of a traditional systems development environment?​ a. ​ Systems are developed and delivered in an
pshichka [43]

Answer:

c. ​ Many applications require substantial desktop computing power and resources.

Explanation:

From the options given, the correct answer is C.

Traditional system development is the development of computer software for a typical computer system.

The other options is true for web based system development environment.

Option A mention web based framework as traditional development environment and this is not correct.

Option B mention scalability and running on multiple hardware. This is not true for traditional development environment as it is not scalable and it doesn't run on multiple hardware concurrently. So B is not correct.

Option C is correct as Many applications require substantial desktop computing power and resources.

Option D is not correct as traditional system development environment is not the platform for internet based development. Internet-based development treats the traditional systems development environment as the platform, rather than just a communication channel.

6 0
3 years ago
Other questions:
  • Letm1, m2,···mnbe distinct numbers on the number line, in the increasing order. Your goalis to color all of them blue. You have
    9·1 answer
  • The organization wants you to avoid situations that make you choose between its overall benefit and your
    13·1 answer
  • What is the relation between Information and Data?
    6·1 answer
  • Enables you to temporarily hide all the open windows except the one you are viewing.
    11·1 answer
  • Two-factor authentication can best be breached by the adversary using:________. a. social engineering attack b. using sniffers l
    10·1 answer
  • ‘The increased availability of mobile digital devices has had a positive impact on how young people use their free time’. Make a
    8·1 answer
  • Write a recursive function that returns true if the digits of a positive integer are in increasing order; otherwise, the functio
    15·1 answer
  • Examples in types of experimental methods <br>​
    14·2 answers
  • What is intellectual property rights law ?​
    8·1 answer
  • You would like to see only the last 15 lines of /home/user/log file on your linux machine. Which command line interface (cli) co
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!