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maksim [4K]
3 years ago
10

In the design phase of the systems development life cycle (SDLC), the _____ design is an overview of the system and does not inc

lude hardware or software choices. Group of answer choices
Computers and Technology
1 answer:
lyudmila [28]3 years ago
5 0

Answer:

"Conceptual" is the correct answer.

Explanation:

  • SDLC would be a particular implementation of a software administration that defines the processes responsible for the creation of such an organization or project, through preliminary feasibility studies to accomplished program activities.
  • The conceptual design seems to be the very first phase of the cycle of brand management, using designs as well as other diagrams or models. It offers an implementation of the study product as a result of a collection of interconnected values and principles about what it will do, function, and look in a user-friendly way.
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Find the equation of a line which has 10 points the following two coordinates: (4, 0) and (3, 4)​
alex41 [277]

Answer:

The equation of the line is y = -4·x + 16

10 points on the line include;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

Explanation:

The given points through which the line passes are;

(4, 0) and (3, 4)

The slope, 'm', of the line is given as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore, the slope of the line is (4 - 0)/(3 - 4) = -4

In point and slope form we can get;

\dfrac{y-0}{x-4} = -4

The equation of the line in point and slope form is therefore;

y = -4·(x - 4) = -4·x + 16

The equation of the line in slope and intercept form is

y = -4·x + 16

10 points on the line are obtained using the equation of the line and the desired x-values input into cells on MS Excel and presented here as follows;

(0, 16), (1, 12), (2, 8), (3, 4), (4, 0), (5, -4), (6, -8), (7, 12), (8, -16), (9, -20), and (10, -24)

8 0
3 years ago
Which of these is a way that a doctor can examine a patient?
SIZIF [17.4K]

Answer:

D. all the above

Explanation:

because doctor uses stethoscope to listen patients heart, he also used hammer to check patients reflexes and also doctor has to listen to the patient.

5 0
3 years ago
Which tool can you use to display hardware utilization statistics that tell you about the operation of your computer?
defon

Performance monitor tool can you use to display hardware utilization statistics.

<h3>what is a performance Monitor?</h3>
  • Performance Monitor is a system monitoring program introduced in Windows NT 3.1. It monitors various activities on a computer such as CPU or memory usage.

To learn more about performance monitoring, refer

to brainly.com/question/12960090

#SPJ4

7 0
2 years ago
A person who breaks into a computer, network, or online site is called
dybincka [34]

Answer:

B: Hacker

Explanation:

literally anything else aren't even real things besides hacker.

5 0
3 years ago
Read 2 more answers
⦁ Consider transferring an enormous file of L bytes from Host A to Host B. Assume an MSS of 536 bytes. ⦁ What is the maximum val
timurjin [86]

Answer:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

Explanation:

a)  There are approximately  2^32 = 4,294,967,296 possible number of the sequence. This number of the sequence does not increase by one with every number of sequences but by byte number of data transferred. Therefore, the MSS size is insignificant. Thus, it can be inferred that the maximum L value is representable by 2^32 ≈ 4.19 Gbytes.

b)  ceil(2^32 / 536) = 8,012,999

The segment number is 66 bytes of header joined to every segment to get a cumulative sum of 528,857,934 bytes of header. Therefore, overall number of bytes sent will be 2^32 + 528,857,934 =  4.824 × 10^9 bytes.  Thus, we can conclude that the total time taken to send the file will be 249 seconds over a 155~Mbps link.

8 0
3 years ago
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