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dalvyx [7]
2 years ago
15

Type a digit that makes this statement true.

Mathematics
2 answers:
posledela2 years ago
7 0

The possible digits that will make 14, 213, 1__2 to be divisible by 4 are;

1, 3, 5, 7 and 9

<h3>Divisibility of Numbers</h3>

We are given the digit as 14, 213, 1__2.

Now, we see that the first of the last two digits is blank and for the give digit 14, 213, 1__2 to be divisible by 4 then the last two digits must be divisible by 4.

Now, since the last 2 digits must be divisible by 4, then it means any singe digit odd number we put in the blank space will yield a combined digit that is divisible by 4. Let us check them;

For 1; 14, 213, 112 ÷ 4 = 3, 553, 278

For 3; 14, 213, 132 ÷ 4 = 3, 553, 283

For 5; 14, 213, 152 ÷ 4 = 3, 553, 288

For 7; 14, 213, 172 ÷ 4 = 3, 553, 293

For 9; 14, 213, 192 ÷ 4 = 3, 553, 298

Read more about divisibility of numbers at; brainly.com/question/24672369

Mrac [35]2 years ago
3 0

Answer:

information down below:

since we know that every thousand has to have at least 3 digits, we would have to add a zero to 14,213,12<u>0</u>. This is because the problem wouldn’t be right! Also, if we divide 14,213,120 by 4, our answer would be 3,553,280. A lot of numbers, but they can be solved!

<h3>Hope this helps!✌️</h3>

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Every even number,except 2,is composite
Degger [83]
Yes. That's correct. Is that what you're asking...? To clarify, prime numbers have a single factor (one and itself) , composite numbers have multiple factors.
5 0
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On a coordinate plane, triangle A B C is shifted 4 units to the right and 2 units up to form triangle A prime B prime C prime. I
zheka24 [161]

Answer:

(x, y) ⟶ (x + 4, y + 2)  

Step-by-step explanation:

If you shift a point four units to the right, x ⟶ x + 4.

If you shift it up two units, y ⟶ y + 2.

If you combine the two shifts into one transformation, the rule becomes

(x, y) ⟶ (x + 4, y + 2)

3 0
3 years ago
Aimee is flying a plane for the first time! The air traffic controller tells her to fly at 500 m above the ground or higher. Wri
Aleonysh [2.5K]
H > =  500...(thats greater then or equal to)
7 0
3 years ago
Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the ai
ollegr [7]

Answer:

The probability that the aircraft  is  overload = 0.9999

Yes , The pilot has to be take strict action .

Step-by-step explanation:

P.S - The exact question is -

Given - Before every​ flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 ​passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.

To find - What is the probability that the aircraft is​ overloaded ?

         Should the pilot take any action to correct for an overloaded aircraft ?

Proof -

Given that,

Mean, μ = 182.7

Standard Deviation, σ = 39.6

Now,

Let X be the Weight of the men

Now,

Probability that the aircraft is loaded be

P(X > 168 ) = P(\frac{x - \mu}{\sigma} > \frac{168 - \mu}{\sigma} )

                 = P( z > \frac{168 - 182.7}{39.6} )

                 = P( z > -0.371)

                 = 1 - P ( z ≤ -0.371 )

                 = 1 - P( z > 0.371)

                 = 1 - 0.00010363

                 = 0.9999

⇒P(X > 168) = 0.9999

As the probability of weight overload = 0.9999

So, The pilot has to be take strict action .

5 0
2 years ago
What is 5x5+4-6x12 my teacher told me the wrong answer i need help
jok3333 [9.3K]
It should be -43 correct me if I’m wrong
6 0
3 years ago
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