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Deffense [45]
3 years ago
13

Lori purchases a new set of watercolor paints and some canvases to create art for her next exhibit. The watercolor paint set cos

ts $15 and the canvases are $24.50 each. If Lori buys 6 canvases, what is the total amount of money she spends for her next exhibit?
A $211.00
B $162.00
C $237.00
D $147.00
Mathematics
2 answers:
horrorfan [7]3 years ago
7 0
Starting with the paints, we have 15$ as our base value. Next, since we add $24.50 for each new canvas bought, 24.5*x=the amount of money for x canvases. Therefore, since 15 is our base value, we have 15+24.5*6=162
NemiM [27]3 years ago
3 0

The answer is B.) $162.00

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Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili
lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

<em>B</em> = bugs are present in a computer program.

<em>D</em> = a de-bugging program detects the bug.

The information provided is:

P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event <em>E </em>given that another event <em>X</em> has already occurred is:

P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}

Use the Bayes' theorem to compute the value of P (B | D) as follows:

P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

                                                                                     =0.3333\times 0.3333\\=0.11108889\\\approx 0.1111

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0
3 years ago
Find the area of the shape.<br> 7 m<br> 5 m<br> 15 m<br> 4 m
Katena32 [7]
Sorry, idk I just need to answer 1 question to keep asking for more
4 0
3 years ago
Twins issac and isaiah were just born issac weighs 6 pounds 2 ounces and isaiah weighs 5 pounds 4 ounces.How many ounces do issa
Ivanshal [37]

Answer: 11\ \text{pounds}\ 6\ \text{ounces}

Step-by-step explanation:

Given

Issac and Isaiah born weighing 6 pounds 2 ounces and 5 pounds and 4 ounces.

1 Pound is equivalent to 16 ounces

Issac weighs

\Rightarrow 6+\dfrac{2}{16}\ \text{Pounds}

Isaiah weighs

\Rightarrow 5+\dfrac{4}{16}\ \text{Pounds}

Their combined weight is

\Rightarrow 6+5+\dfrac{2}{16}+\dfrac{4}{16}\\\\\Rightarrow 11+\dfrac{6}{16}\ or\\\\\Rightarrow 11\ \text{pounds}\ 6\ \text{ounces}

5 0
3 years ago
A bag contains 5 blue, 3 red, 6 green, 9 orange, and 20 black marbles. What is the ratio of the number of blue marbles to the nu
barxatty [35]

Answer:

C

Step-by-step explanation:

blue+green=15

blue is 5

5 to 15

4 0
3 years ago
Read 2 more answers
What is 0.31 written as a percent?
aalyn [17]
It is 31%.

To explain, you have to just have to multiply 0.31 by 100, and then add a percentage sign.
7 0
3 years ago
Read 2 more answers
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